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professor190 [17]

3 years ago

7

Please help!!!! Thank you!!!!!

1 answer:

GuDViN [60]3 years ago

4 0

Answer: The answer is 3/8

Step-by-step explanation: First you figure out your expression: 7/8 - 1/2. Then you find a common denominator, which will be 8. To make one-half have a denominator of 8, multiply by 4/4. 1/2*4/4=4/8. To finish, subtract 7/8-4/8 and you get 3/8.

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what is the answer to this question and how??

Lesechka [4]

Answer:

maybe there's a typo, that dot usually represents the multiplication, and I got 5.52

4 0

3 years ago

Which of the following relations is NOT a function?

topjm [15]

According to Wikipedia: "<span>In mathematics, a function is a relation between a set of inputs and a set of permissible outputs with the property that each input is related to exactly one output."

So based of this we need to look for a set where one of the x values or the y values is the same, and the other number is different.

Answer:
B.
(1,4) and (1,1) both have the same x, but different y!
</span>

5 0

3 years ago

Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-

djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

$A(x_{1}, y_{1}})=(-20, 25)$

$B(x_{2}, y_{2}})=(30, 25)$

$C(x_{3}, y_{3}})=(30, -10)$

$D(x_{4}, y_{4}})=(-20, -10)$

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

$d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ ----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

$AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}$

$AB=\sqrt{(30+20)^{2}}$

$AB=\sqrt{(50)^{2}$

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

$d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}$

$BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}$

$BC=\sqrt{(-35)^{2}}$

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

$d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}$

$DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}$

$DC=\sqrt{(30+20)^{2}}$

$DC=\sqrt{(50)^{2}}$

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

$d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}$

$AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}$

$AD=\sqrt{(-20+20)^{2}+(-35)^{2}}$

$AD=\sqrt{(-35)^{2}}$

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

7 0

3 years ago

I NEED HELP ON THIS PLZZZ HELPP

adell [148]

Answer:

$76 \: {in}^{2}$

Step-by-step explanation:

Area of the figure = Are of square with side 8 in + 2 times the area of one triangle with base (8 - 5 = 3) 3 in and height 4 in

$= {(8)}^{2} + 2 \times \frac{1}{2} \times 3 \times 4 \\ \\ = 64 + 12 \\ \\ = 76 \: {in}^{2}$

3 0

3 years ago

Reduce to simpleast form. -5/8 - (-4/3)=

vfiekz [6]

$-\frac{5}{8} -(-\frac{4}{3} )= -\frac{5}{8}^{(3} + \frac{4}{3}^{(8} = \frac{-15+32}{24}= \frac{17}{24}$

3 0

3 years ago