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Anon25 [30]
3 years ago
7

What’s the scientific notation on -0.00346

Mathematics
1 answer:
NeTakaya3 years ago
4 0
3.....................
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Match each pair of points to the equation of the line that is parallel to the line passing through the points.
Tanya [424]
If we identify the lines by ...
  1. y = -0.5x -3
  2. y = -3.5x -15
  3. y = 5x +19
  4. y = 1.25x +4

Then the matches are ...
  BC - 2
  DE - 1
  FG - none
  HI - 4
  JK - none
  LM - 3

_____
Whenever there is a lot of repetitive math to do, I usually find it easier to let a calculator or spreadsheet do it. Here, the graphing calculator is computing the slope between the points. The slopes of parallel lines are the same.

4 0
3 years ago
What is the length of MN
Dafna1 [17]
Because this is an isosceles triangle, 3x = x + 10.  Thus, 2x + 10 and x = 5.

With x=5, MN has the length 5+10, or 15.
5 0
3 years ago
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All angles are right angles this describes a parallelogram, rhombus, rectangle, or a square (there can be more than one answer
Sidana [21]
Rectangle and square
7 0
3 years ago
Matt's family is thinking about buying a family pass to a park. The pass is $130 for a family of 6.
wolverine [178]

Answer:

he can save $80

Step-by-step explanation:

first you need to multiply 35 x 6 the answer to that is 210

then you need to subtract 130 from 210

and the answer is 80

therefore Matt's family can save $80

6 0
3 years ago
PLEASE HELP ASAP, ABSURD ANSWERS GET REPORTED GOOD ANSWERS GETT BRAINLIEST +30 POINTSS, PLEASE ANSWER ASAP
makkiz [27]
15. The same polar coordinate as point P will be arrived if: (1) a full rotation of 2nπ is performed or (2) a rotation of (2n+1)π is performed and r is negated. Among the choices, we can see exactly one option with coordinates that follow these two rules, and it is choice A.

ANSWER: A. (1, pi divided by 3 + 2nπ) or (-1, pi divided by 3 + (2n+1)π)

16. To convert the coordinate (3, -3) to polar, we just let x be rcosθ and y be rsinθ. We can get r by solving r^{2}=x^{2}+y^{2} while we can get θ by solving for \theta=arctan(\frac{y}{x}).

r^{2}=(3)^{2}+(-3)^{2}
r=3sqrt(2)

\theta=arctan(\frac{-3}{3})=315degrees

Therefore, one pair of polar coordinates would be (3 square root of 2, 315 degrees) and another one would be (-3 square root of 2, 135 degrees) [note the rule we stated in number 15].

ANSWER: A. (3 square root of 2, 315 degrees), (-3 square root of 2, 135 degrees)

17. Based on your definition that the graph is "circular" with some indentation on the left toward the origin, we can only deduce that the limacon with the form r = a + bcosθ has a value of a that is greater than b. Looking at the choices, our options will be narrowed down to 2 (B and D). Among these, a graph that will look like a circle would be a convex limacon and a limacon of this kind would require that the value of a should be greater than or equal to the value of 2b. Therefore, this will narrow down the answer to option D.

ANSWER: D. r = 4 + cos θ

18. To test for symmetry about the x-axis, we replace the variables r and θ with r and -θ respectively or -r and π-θ. The equation will be symmetric if it will be unchanged (i.e. the same points will still satisfy the new equation).

r=4-4cos\theta
r=4-4cos(-\theta)
-r=4-4cos(\pi-\theta)

If you examine closely, the same set of points will satisfy the equations above. Therefore, the equation is symmetric about the x axis.

For symmetry about the y-axis, we replace r and θ with -r and -θ.

r=4-4cos\theta
-r=4-4cos(-\theta)

Unfortunately, the equation was changed upon substitution therefore we know that it is not symmetric about the y-axis.

For symmetry about the origin, we just replace r and θ with -r and θ respectively.

r=4-4cos\theta
-r=4-4cos\theta

These two equations are not also similar so no symmetry about the origin is exhibited. 

ANSWER: B. x-axis only

19. Let's consider the general form of the ellipse: \frac{x^{2}}{b^{2}}+\frac{y^{2}}{a^{2}}=1.

From the problem we know that a is equal to 58 since we are given the fact that the height of the tunnel is 58ft. To find b, we use the fact that the point (21,29) is a point on the ellipse as stated in the problem.

\frac{x^{2}}{b^{2}}+\frac{y^{2}}{58^{2}}=1
\frac{21^{2}}{b^{2}}+\frac{29^{2}}{58^{2}}=1
\frac{21^{2}}{b^{2}}+0.25=1
441=0.75b^{2}
b^{2}=588

ANSWER: \frac{x^{2}}{588}+\frac{y^{2}}{3364}=1

20. For this item, we follow similar rules stated in item #18. To test for symmetry, we need to examine if the equation will remain unchanged after performing substitutions. 

r=4cos5\theta

x-axis:
r=4cos(-5\theta)
-r=4-4cos[5(\pi-\theta)]

y-axis:
-r=4cos(-5\theta)

origin:
-r=4cos5\theta

If you examine the equations, you'll see that it is only symmetric at the x-axis.

ANSWER: The equation is symmetric about the x-axis.
4 0
3 years ago
Read 2 more answers
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