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3 years ago

11

The cost of a sapling of Mango, Jamun and Peepal is Rs 25, Rs 15 and Rs 10 each. The labour

1 answer:

alekssr [168]3 years ago

6 0

Answer:

fifty rupee 70paise answer

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How to do this pls:( using PEMDAS

Kryger [21]

Answer: x y

-2 15

-1 9

0 7

1 9

2 15

3 25

Step-by-step explanation:you always do the exponent first, then you multiply that by that two, and then you add 7.

7 0

3 years ago

Jamisha is solving the equation

Phantasy [73]

Answer: she made a mistake between 1 and 2

3 0

3 years ago

What are the solutions to the quadratic equation below in factored form?

saw5 [17]

Answer:

$\cfrac{-4}{3}$ and $\cfrac{1}{2}$ .

Step-by-step explanation:

Equation:

$\rm \: \: (2x - 1)(3x + 4) = 0$

Solution:

Set factors equal to zero,that is:

$(2x - 1) = 0 \: \: \: \: \: \: \: \: \: \: \: ...(1)$

$(3x + 4) = 0 \: \: \: \: \: \: \: \: \: \: \: \: ...(2)$

Solving for equation 1:

$2x - 1 = 0$
$2x = 0 + 1$
$2x = 1$

$\boxed{x = \cfrac{ 1}{2} }$

Solving for equation 2:

$3x + 4 = 0$
$3x = 0 - 4$
$3x = - 4$

$\boxed{x = \cfrac{ - 4}{3} }$

Hence,the solutions to the quadratic equation in factored form is $\cfrac{-4}{3}$ and $\cfrac{1}{2}$ .

$\rule{225pt}{2pt}$

Good luck on your assignment!

4 0

2 years ago

Read 2 more answers

Divide . round your answer to the nearest tenth 8÷8766

melamori03 [73]

Answer: 0 (zero)

<em>Good Luck!</em>

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4 0

3 years ago

Read 2 more answers

Construct a 95% confidence interval for the population mean, μ. Assume the population has a normal distribution. A random sample

GuDViN [60]

Answer: $(628.48,\ 661.52)$

Step-by-step explanation:

Given : Sample size : $n=16$ , which is a small sample (, 30) so we use t-test.

Sample mean : $\overline{x}=645 \text{ hours}$

Standard deviation : $\sigma = 31 \text{ hours}$

Significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=2.131$

The confidence interval for population mean is given by :-

$\overline{x}\pm t_{n-1,\alpha/2}\dfrac{\sigma}{\sqrt{n}}\\\\=645\pm(2.131)\dfrac{31}{\sqrt{16}}\\\\\approx645\pm16.52\\\\=(645-16.52,\ 645+16.52)\\\\=(628.48,\ 661.52)$

Hence, a 95% confidence interval for the population mean $\mu$ = $(628.48,\ 661.52)$

6 0

3 years ago