In mathematics the curve that graphically represents the sine function and also that function itself is called sinusoid or sinusoid. It is a curve that describes a repetitive and smooth oscillation. It can be represented as y(x) = a sin (ωx+φ) where a is the amplitude, ω is the angular velocity with ω=2πf, (ωx+φ) is the oscillation phase, and φ the initial phase.

The period T of the sin function is T=1/f, from the equation ω=2πf we can clear f and substitute in T=1/f.

f=ω/2π

Substituting in T=1/f:

T=1/ω/2π -------> T = 2π/ω

For the example y = a sin bx, we have that a is the amplitude, b is ω and the initial phase φ = 0. So, we have that the period T of the function a sin bx is:

T=2π/|b|

7 0

2 years ago

Solve for x in the equation x^2-14+31=63

Bingel [31]

To solve for a variable, you need to get it (x) by itself.

x² - 14 + 31 = 63 Add 31 to -14
x² + 17 = 63 Subtract 17 from both sides of the equation
x² = 46 Square root both sides
x = $\pm \sqrt{46}$

Check your work by plugging in $\sqrt{46}$ for x and then $- \sqrt{46}$ .

$\sqrt{46}$ ² - 14 + 31 = 63 Square $\sqrt{46}$
46 - 14 + 31 = 63 Subtract 14 from 46
32 + 31 = 63 Add
63 = 63

$- \sqrt{46}$ ² - 14 + 31 = 63 Square $- \sqrt{46}$
46 - 14 + 31 = 63 Subtract 14 from 46
32 + 31 = 63 Add
63 = 63

So, x is $\sqrt{46}$ and $- \sqrt{46}$ .

3 0

3 years ago

3x power of 2+ 5x+2=0<br><br>what does x equal

In-s [12.5K]

Let's solve your equation step-by-step.
2+5x+2=0
Step 1: Simplify both sides of the equation.
2+5x+2=0
(5x)+(2+2)=0(Combine Like Terms)
5x+4=0
5x+4=0
Step 2: Subtract 4 from both sides.
5x+4−4=0−4
5x=−4
Step 3: Divide both sides by 5.
5x
5
=
−4
5
x=
−4
5

Answer:
x=
−4
5

4 0

2 years ago