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joja [24]
3 years ago
15

I think of a number. I add 3 then divide it by 2. My answer is 12. Form an equation and solve it to find my number.

Mathematics
2 answers:
Sunny_sXe [5.5K]3 years ago
7 0

Answer:

21

Step-by-step explanation:

21 plus 3 equals 24 divided by 2 equals 12

Scilla [17]3 years ago
7 0

Answer:

The answer is 21.

Step-by-step explanation:

21+3 equals 24, and 24 divided by 2 equals 12. And 12x2 equals 24. :)

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HELP PLEASE WILL GIVE BRAINLIEST BE QUICK
slamgirl [31]

Answer:

(2,0) and (4,0)

Step-by-step explanation:

The roots of the parabola are the points where the value of the function is zero, i.e., where the graph crosses the x-axis.

(2,0) and (4,0)

7 0
3 years ago
*Please answer before 5:45! I'll award brainliest!*
FromTheMoon [43]

Answer:

A

Step-by-step explanation:

Vertical angles are angles that are formed by 2 lines and are directly accross from each other. They do not share a ray, however they are always the same number of degrees.

so then the answer would be A, ∠ERT and ∠MRC since they are directly across from each other.

4 0
3 years ago
Help solving this math question
olga_2 [115]

22. B) $65,000,000 per year.

23. B) Education.

Step-by-step explanation:

Step 1; To find the average rate of change in annual budget between the two given years. We divide the difference in values for the two years by the period in between the two years. In 2008, the budget was $358,708,000 while in 2010 it was $488,106,000. The period in between was 2 years i.e 2009 and 2010.

The average rate of change = \frac{488,106,000-358,708,000}{2} = \frac{129,398,000}{2} = $64,699,000 per year.

So the average rate of change was $64,699,000 which approximately equals option B. $65,000,000.

Step 2; To find the human resources program's 2007 to 2010 ratio we divide the value in 2007 to the value in 2010. To find the other similar ratio, we divide the value in 2007 to the value in 2010 for all the other programs and determine which is closest to the human resources program.

Human resources program ratio = \frac{4,051,050}{5,921,379} = 0.6841,

Agricultural / natural resources ratio = \frac{373,904}{488,106} = 0.766,

Education's ratio = \frac{2,164,607}{3,008,036} = 0.7196,

General government's ratio = \frac{14,347,325}{14,716,155} = 0.9749,

Highways and transportation's ratio = \frac{1,468,482}{1,773,893} = 0.827,

Public safety's ratio = \frac{263,463}{464,233} = 0.5675.

The Human resources' program ratio is 0.6841 and the closest is Education's ratio which is 0.7196. So education is the answer.

4 0
3 years ago
Find S12 for geometric series: (-7.5) + 15 + (-30) + ...
kolezko [41]

Answer:

S12 for geometric series: (-7.5) + 15 + (-30) + ... would be: 10237.5

Step-by-step explanation:

Given the sequence to find the sum up-to 12 terms

(-7.5) + 15 + (-30) + ...

As we know that

A geometric sequence has a constant ratio 'r' and is defined by

a_n=a_1\cdot r^{n-1}

\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_{n+1}}{a_n}

\frac{15}{\left(-7.5\right)}=-2,\:\quad \frac{\left(-30\right)}{15}=-2

\mathrm{The\:ratio\:of\:all\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}

r=-2

\mathrm{The\:first\:element\:of\:the\:sequence\:is}

a_1=\left(-7.5\right)

a_n=a_1\cdot r^{n-1}

\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:

a_n=\left(-7.5\right)\left(-2\right)^{n-1}

a_n=-\left(-2\right)^{n-1}\cdot \:7.5

\mathrm{Geometric\:sequence\:sum\:formula:}

a_1\frac{1-r^n}{1-r}

\mathrm{Plug\:in\:the\:values:}

n=12,\:\spacea_1=\left(-7.5\right),\:\spacer=-2

  =\left(-7.5\right)\frac{1-\left(-2\right)^{12}}{1-\left(-2\right)}

  =-7.5\cdot \frac{1-\left(-2\right)^{12}}{1+2}

\mathrm{Multiply\:fractions}:\quad \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}

  =-\frac{-30712.5}{1+2}          ∵  \left(1-\left(-2\right)^{12}\right)\cdot \:7.5=-30712.5

 =-\frac{-30712.5}{3}

 =\frac{30712.5}{3}

 =10237.5

Thus, S12 for geometric series: (-7.5) + 15 + (-30) + ... would be: 10237.5        

5 0
4 years ago
Given it's midpoint and one endpoint apply the midpoint formula and solve for x and y midpoint (22,15) endpoint (18,6
Nutka1998 [239]
Midpoint formula

mid of (x1,y1) and (x2,y2) is
( \frac{x2+x1}{2}, \frac{y2+y1}{2})

so

(22,15)=( \frac{18+x1}{2}, \frac{6+y1}{2})
therefor

22=\frac{18+x1}{2}
and
15=\frac{6+y1}{2}

slv each
22=\frac{18+x1}{2}
times both sides by 2
44=18+x1
minus 18 both sides
26=x1

15=\frac{6+y1}{2}
times both sides by 2
30=6+y1
minus 6
24=y1

the other point is (26,24)

4 0
3 years ago
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