A 55 kg softball player slides into second base, generating 940 J of thermal energy in her legs and the ground. How fast was she
1 answer:
When the player slides into the base, all its kinetic energy converts into thermal energy in the legs and the ground.
The thermal energy generated is 940 J, so the initial kinetic energy of the player must be 940 J as well:
where m=55 kg is the mass of the player and v is his speed. Re-arranging the fomula, we can find the value of his speed, v:
The thermal energy generated is 940 J, so the initial kinetic energy of the player must be 940 J as well:
where m=55 kg is the mass of the player and v is his speed. Re-arranging the fomula, we can find the value of his speed, v:
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Answer:
d = 10.2 m
Explanation:
When the car travels up the inclined plane, its kinetic energy will be used to do the work in climbing up. So according to the law of conservation of energy, we can write that:
where,
m = mass of car
v = speed of car at the start of plane = (36 km/h)(1000 m/1 km)(1 h/3600 s)
v = 10 m/s
F = force on the car in direction of inclination = W Sin θ
W = weight of car = mg
θ = Angle of inclinition = 30°
d = distance covered up the ramp = ?
Therefore,
<u>d = 10.2 m</u>