Answer: 6.65 rad/s
Explanation:
Firstly, we need to know that according the kinetic theory of gases, the average kinetic energy
of a molecule with
degrees of freedom is:
(1)
Where:
because oxigen is a diatomic molecule and has 5 degrees of freedom
is the Boltzman constant
is the temperature
Then:
(2)
(3) With this value of average kinetic energy we can find the average angular velocity, with the following equation:
(4)
Where:
is the moment of inertia
is the angular velocity
Now,
(5)
Being
the molar mass of Oxigen molecule and
the distance between atoms
(6)
(7)
Substituting (7) and (3) in (4):
(8)
Finding
:
(9) This is the average angular velocity for a molecule of O2
Answer:
b
Explanation:
because if you freeze somthing you do not gain heat you loss heat.
If the atoms that share electrons have an unequal attraction for electrons, the bond is called a Polar covalent bond.
<h3><u>Explanation:</u></h3>
A covalent chemical bond is formed in case of two different non-metals when one or more electron pairs are shared between bonding atoms. A difference in electronegativity of subsequent atoms of a covalent bond leads to formation of a small net charge around nucleus of each atom, pulling the shared electrons to one side of the bond, to the nucleus which has higher electronegativity.
HCl is an example of polar covalent bond and the HCl bond has Chlorine more electronegative. The bonding electrons are more close to Cl than H and hence Cl is partially negatively charged than H which has partial positive charge (HCl bond :
). When electrons shared in a covalent bond have equal attraction, the bond is a Non-Polar covalent bond.
(a) 6.04 rev/s
The speed of the ball is given by:

where
is the angular speed
r is the distance of the ball from the centre of the circle
In situation 1), we have

r = 0.600 m
So the speed of the ball is

In situation 2), we have

r = 0.900 m
So the speed of the ball is

So, the ball has greater speed when rotating at 6.04 rev/s.
(b) 
The centripetal acceleration of the ball is given by

where
v is the speed
r is the distance of the ball from the centre of the trajectory
For situation 1),
v = 30.6 m/s
r = 0.600 m
So the centripetal acceleration is

(c) 
For situation 2 we have
v = 34.1 m/s
r = 0.900 m
So the centripetal acceleration is
