Answer:
Draw tangents to the graph at 1.0 s and 5.0 s. 0. 1. 2. 3. 4. 5. 6. 0 ... When the velocity component is negative, the extra displacement during ... 2 - 3 min. constant acceleration component until the car stops. ..... ii). The gravitational force and the drag force are doing work on the object. .... N) × (0.5 m) = 5 × 10. 2.
Explanation:
From the given information, it's not possible to find the mass or the volume of the sample.
Density is their RATIO, but you can't tell if the sample is the size of an ant or a school-bus.
Answer:
120 kg•m/s.
Explanation:
From the question given above, the following data were obtained:
Case 1
Mass of object = M
Velocity of object = V
Momentum = 15 kg•m/s
Case 2
Mass of object = 2M
Velocity of object = 4V
Momentum = ?
Momentum is defined as follow:
Momentum = mass × velocity
The momentum of object in case 2 can be obtained as follow:
From case 1
Momentum = mass × velocity
15 = M × V
15 = MV ....... (1)
From case 2:
Momentum = mass × velocity
Momentum = 2M × 4V
Momentum = 8MV ....... (2)
Finally , substitute the value of MV in equation 1 into equation 2.
Momentum = 8MV
MV = 15
Momentum = 8 × 15
Momentum = 120 kg•m/s
Therefore, an object with a mass of 2M and 4V would have a momentum of 120 kg•m/s
Mohs hardness scale. hope this helps
The correct answer is B) less then the total kinetic energy of the cylinder,
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