An internal combustion engine uses fuel, of energy content 44.4 MJ/kg, at a rate of 5 kg/h. If the efficiency is 28%, determine
1 answer:
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Answer:
The magnitude = 10.30 m
The direction of the vector proceeds at angle of 119.05°
Explanation:
Given that:
A vector has component
= -5 m and
= 9 m
The magnitude of vector can be represented as:
=
=
=
=
= 10.30 m
If we make an angle
with y- axis:
Then; tan =
tan =
tan = 0.555
= tan⁻¹ (0.555)
= 29.05°
Angle with positive x-axis = 90 +
= 90° + 29.05°
= 119.05°
Answer: 4,438.96m
Explanation:
(kindly find attachment below)
From the attachment below, it can be seen that the resultant displacement and the other 2 displacements form a right angle triangle, with A+B as the hypotenus, 3.2km as the opposite and the displacement B as the adjacent.
By using phythagoras theorem
H² = O² + A²
(5.38)² = (3.20)² + B²
28.944 = 10.24 + B²
B² = 28.944 - 10.24
B² = 18.7044
B = √18.7044
B = 4.439km to meter is 4.439 * 1000 = 4,438. 96m
