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Morgarella [4.7K]
3 years ago
10

−px+r=−8x−2 solve for X

Mathematics
2 answers:
Arlecino [84]3 years ago
5 0
-8x-2=0
-8x=2
8x=-2
x=-1/4
luda_lava [24]3 years ago
5 0

Answer:

\frac{-2-r}{-p+8}.

Step-by-step explanation:

-px+r= -8x-2

-px+8x = -2-r

x(-p+8) = -2-r

x = \frac{-2-r}{-p+8}.

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A universal set U consists of elements. If sets​ A, B, and C are proper subsets of U and ​n(U)​, ​n(A ​B)​n(A ​C)​n(B ​C)​, ​n(A
iragen [17]

Answer:

n(A\ u\ B) = 10

n(A'\ u\ C) = 10

n(A\ n\ B)' = 6

Step-by-step explanation:

Given

n(U) = 12

n(A\ n\ B) =n(A\ n\ C) = n(B\ n\ C) =6

n(A\ n\ B\ n\ C)=4

n(A\ u\ B\ u\ C)=10

Required

Solve a, b and c

There are several ways to solve this; the best is by using Venn diagram (see attachment for diagram)

Solving (a):

n(A\ u\ B)

This is calculated as:

n(A\ u\ B) = n(A) + n(B) - n(A\ n\ B)

From the attachment

n(A) = 0+2+4+2 = 8

n(B) = 0+2+4+2 = 8

n(A\ n\ B) = 4 +2 = 6

So:

n(A\ u\ B) = 8 + 8 - 6

n(A\ u\ B) = 10

Solving (b):

n(A'\ u\ C)

This is calculated as:

n(A'\ u\ C) = n(A') + n(C) -n(A'\ n\ C)

From the attachment

n(A) = n(U) - n(A) = 12 - 8 = 4

n(C) = 0+2+4+2 = 8

n(A'\ n\ C) = 2

So:

n(A'\ u\ C) = 4 + 8 - 2

n(A'\ u\ C) = 10

Solving (c):

n(A\ n\ B)'

This is calculated as:

n(A\ n\ B)' = n(U) - n(A\ n\ B)

n(A\ n\ B)' = 12- 6

n(A\ n\ B)' = 6

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3 years ago
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Step-by-step explanation:

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