Answer:
first off, this may be completely wrong, but I did try my best. You need to clarify what this is for so I went with the easiest route, solving for variables.
P=0
X= - 3/4
Step-by-step explanation:
P(-2)=-3+4x
Solving for X
-2P=-3+4x
-2(0)=-3+4x
-3=4x
- 3/4=X
Solving For P
P(-2)=3+4(- 3/4)
P(-2)3-3
P=0
Answer: The percent of red lights last between 2.5 and 3.5 minutes = 95.44% approx.
Step-by-step explanation:
Given: Mean time = 3 minutes
standard deviation = 0.25 minutes
The probability of red lights last between 2.5 and 3.5 minutes :-

The percent of red lights last between 2.5 and 3.5 minutes = 95.44% approx.
I believe its C, It's just process of elimination.
F(1) = 1^3 + 3(1)^1 - 3 - 1 = 1 + 3 - 3 - 1 = 0
so one zero is x = 1, and x-1 is a factor
dividing f(x) by x - 1 gives x^2 + 4x + 1
x = [-4 +/- sqrt (16 - 4)] / 2
x = -0.27, -3.73
zeroes are 1 , -0.27 and -3.73 Answer