5 because 25 divided by 5 is 5
<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
Answer:
5.3
Step-by-step explanation:
a² + b² =² c² the Pythagorean theorem
RQ² + RS² = QS² Solve RS
6² + RS² = 8²
RS² = 64 -36
RS² = 28
RS = √28 28 is slightly > 25 and since √25 =5
RS = 5.3 actually 5.2915 to a few more significant digits
I could be wrong, but it seems that there are only 2 possible squares in this grid.
•One square has a side length of 2, meaning that the area is 2x2 which is 4 units squared (can be written as 4 units^2)
•The other square has side lengths of 1. 1x1=1 unit^2.
Answer: C
Step-by-step explanation:
