A: Equilateral
B: Obtuse
C: Obtuse
D: Right
E: Obtuse
F: Acute
The distribution of the values obtained from a simple random sample of size n from the same population is incorrect.
<h3>What is
sampling distribution?</h3>
The sampling distribution of a statistic of size n is the distribution of the values obtained from a simple random sample of size n from the same population.
The sampling distribution is the process of getting a sample through simple random techniques from the sample population.
So, it is incorrect that the distribution of all values of the statistic when all possible samples of the same size n are taken from the same population.
Learn more about sampling distribution here:
brainly.com/question/3663642
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Answer:
f(n) = -11 + 22(n - 1)
<em>f(1) is your initial value.</em>
f(1) = -11 + 22(1 - 1)
f(1) = -11
------------------------------------------------------------
f(2) = -11 + 22(2 - 1) = 11
f(3) = -11 + 22(3 - 1) = 33
f(4) = -11 + 22(4 - 1) = 55
<em>f(n - 1) is just a notation for the previous term</em>
<em>Using the equation f(n) = f(n - 1) + _______ :</em>
f(2) = f(1) + ??? = 11
f(3) = f(2) + ??? = 33
f(4) = f(3) + ??? = 55
f(2) = -11 + ??? = 11
f(3) = 11 + ??? = 33
f(4) = 33 + ??? = 55
f(2) = -11 + 22 = 11
f(3) = 11 + 22 = 33
f(4) = 33 + 22 = 55
∴ f(n) = f(n - 1) + 22
.
Answer: 2s + 1
Explanation:
1) Given expression: 6s² - 7s- 5 = (3s - 5) ( )
2) The missing factor ( ) is such that when it is multiplied by (3s - 5) the product is 6s² - 7s- 5.
3) Since the first term of the first factor starts with 3s, the first term of the second factor shall be 2s (since they have to yield 6s²). Then, you can write:
6s² - 7s- 5 = (3s - 5) (2s + )
4) The second term of the missing factor is positive because the product (+)(-) = (-) which is the sign of the third term of the polynomial.
5) The second term is such that when multiplied by - 5 is equal to the last term of the polynomial (also - 5), so this second terms is +1.
And you get: 6s² - 7s- 5 = (3s - 5) (2s + 1)
6) You can expand, using distributive property to confirm the result:
(3s - 5) (2s + 1 ) = (3s)(2s) + (3s)(1) - (5)(2s) -(5)(1) = 6s² - 7s- 5, which confirms the result.
