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jolli1 [7]
4 years ago
14

A pulley of diameter 49.0 in revolves at 1860 rpm. What is the diameter of a second pulley, in inches, if it rotates at 620 rpm?

Physics
1 answer:
Rudiy274 years ago
4 0

Answer;

First pulley;

Diameter; 49.0, revolutions 1860 rpm

Second pulley;

Diameter; x ; revolutions 620 rpm

To get the diameter of the second pulley;

= (Diameter of the first × Revolutions of the first)/ revolutions of the second.

= (49 ×1860)/620

= 147

Thus; the diameter of the second pulley is 147.

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<u>Now the horizontal component of velocity:</u>

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<u>The vertical component of the velocity:</u>

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<u>Now this height should be the maximum height of the tossed apple where its velocity becomes zero.</u>

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u'=10.259\ m.s^{-1} is the initial velocity of tossing the apple.

<u>Time taken to reach this height:</u>

v'=u'-g.t'

0=10.259-9.8\times t'

t'=1.0469\ s

<u>We observe that </u>t>t'<u> hence the time after the launch of the projectile after which the apple should be tossed is:</u>

\Delta t=t-t'

\Delta t=1.0642-1.0469

\Delta t=0.0173\ s

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