Question

A tire company is selling two different tread patterns of tires. Tire x sells for $75.00 and tire y sells for $85.00.Three times the number of tire y sold must be less than or equal to twice the number of x tires sold. The company has at most 300 tires to sell.
What is the maximum revenue that the company can make?



$13,500

$22,500

$23,700

$25,500

Answer 1

Let

x-------> the number of x tires sold

y-------> the number of y tires sold

we know that

$3y \leq 2x$ ------> equation $1$

$x+y \leq 300$ ------> equation $2$

using a graph tool

see the attached figure

the solution is the shaded area

the maximum revenue that the company can make is for the point $(180,120)$

$x=180\ tires\\ y=120\ tires\\ Revenue=75*180+85*120\\ Revenue=23,700$

therefore

the answer is the option

$$23,700$

Answer 2

23,700 is the revenue they can make at most