Answer:
We know that:
H(x) = |1 - x^3|
and:
We want to write H(x) as f( g(x) ) , such that for two functions:
So we want to find two functions f(x) and g(x) such that:
f( g(x) ) = |1 - x^3|
Where neither of these functions can be an identity function.
Let's define g(x) as:
g(x) = x^3 + 2
And f(x) as:
f(x) = | A - x|
Where A can be a real number, we need to find the value of A.
Then:
f(g(x)) = |A - g(x)|
and remember that g(x) = x^3 + 2
then:
f(g(x)) = |A - g(x)| = |A - x^3 - 2|
And this must be equal to:
|A - x^3 - 2| = |1 - x^3|
Then:
A = 3
The functions are then:
f(x) = | 3 - x|
g(x) = x^3 + 2
And H(x) = f( g(x) )
5 times the Sum of 3 and 4, then subtract 4
Answer: -3/2x + 3 ⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀
Answer:
x=6, x=0
Step-by-step explanation:
+ 
= 25
+ 
= 25
x=6, x=0
