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Alexxandr [17]
3 years ago
8

Your cell phone company has a reward club. For every three texts you send you get 20 points. You need 1800 point for a prize. Ho

w many texts do you need to send to get a prize
Mathematics
1 answer:
Sliva [168]3 years ago
7 0

Answer: 270


Step-by-step explanation:

Given: For every three texts you send you get 20 points.

Let x be the number of text need to send to score 1800 points.

Also the number of points is directly proportional to the number of texts,

Therefore,

\frac{3}{20}=\frac{x}{1800}\\\Rightarrow\ x=\frac{1800\times3}{20}\\\Rightarrow\ x=270

Hence, we need to send 270 texts to get the prize.


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2 years ago
Please help solve this system of equations
stepan [7]

Make a substitution:

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Then the system becomes

\begin{cases}\dfrac{2\sqrt[3]{u}}{u-v}+\dfrac{2\sqrt[3]{u}}{u+v}=\dfrac{81}{182}\\\\\dfrac{2\sqrt[3]{v}}{u-v}-\dfrac{2\sqrt[3]{v}}{u+v}=\dfrac1{182}\end{cases}

Simplifying the equations gives

\begin{cases}\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81}{182}\\\\\dfrac{4\sqrt[3]{v^4}}{u^2-v^2}=\dfrac1{182}\end{cases}

which is to say,

\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81\times4\sqrt[3]{v^4}}{u^2-v^2}

\implies\sqrt[3]{\left(\dfrac uv\right)^4}=81

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Substituting this into the new system gives

\dfrac{4\sqrt[3]{v^4}}{(\pm27v)^2-v^2}=\dfrac1{182}\implies\dfrac1{v^2}=1\implies v=\pm1

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Answer:

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Step-by-step explanation:

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computing

When i=0 -> 5 \times (-2)^0 =5

When i=1 -> 5 \times (-2)^1 = -10

...

When i=7 -> 5 \times (-2)^7 = --640

then replacing each term we have

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For the second equation we'll have 9 terms, solving in a similar fashion

When i=1 -> \frac{1}{4}1=0.25

When i=2 -> \frac{1}{4}2=0.50

When i=3 -> \frac{1}{4}3=0.75

...

When i=9 -> \frac{1}{4}9=2.25

So we have 0.25 + 0.50 + 0.75 + 1.00 + 1.25 + 1.50+ 1.75 +2.00 +2.25

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