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3 years ago

Can I get help with this please

Mathematics

1 answer:

andriy [413]3 years ago

4 0

Hi, this should be correct. Hope this helps :)

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What is the length of the hypotenuse of right UVW shown?

photoshop1234 [79]

Answer:

Step-by-step explanation:

8 0

3 years ago

Your friend has $80 when he goes to the fair. He spends $4 to enter the fair and $12 on food. Rides at the fair cost $1.25 per r

masha68 [24]

His total money is: $80
He spent $16 for the entrance of the fair and food.

80-(4+12) = 64
subtracting $1.25 per ride = -1.25x

Therefore gives the function:
f(x) = -1.25x + 64

4 0

3 years ago

Read 2 more answers

Change general form of hyperbola into standard: -x^2 + y^2 -16x + 14y - 251 = 0

topjm [15]

Answer:

(y+7)²/364 - (x+8)²/364 = 1

Step-by-step explanation:

This is the standard form of a vertical hyperbola (y-k)²/a² - (x-h)²/b² = 1

so, (y²+14y+?) - (x²+16x+?) = 251

(y²+14+49)-49 - (x²+16x+64)-64 = 251

(y+7)² - (x+8)² = 251 + 49 + 64

(y+7)² - (x+8)² = 364

(y+7)²/364 - (x+8)²/364 = 1

7 0

4 years ago

Brainliest + 20 pts to whoever helps pls!!

Blizzard [7]

Answer:

Correct option is (a). 60.391 and 101.879; because the test statistic is in a critical region, the test rejects the null hypothesis.

Step-by-step explanation:

A Chi-square test for population variance is used to perform this test.

The standard deviation is, 2.0 minutes.

Then the variance is, 4.0 minutes.

The hypothesis for this test is:

H₀: The population variance of all commute times is equal to 4.0 minutes, i.e. σ² = 4.

Hₐ: The population variance of all commute times is not equal to 4.0 minutes, i.e. σ² ≠ 4.

The test statistic is:

$\chi^{2}_{calc.}=\frac{(n-1)s^{2}}{\sigma^{2}}$

The critical region of this test is defined as:

Reject H₀ if $\chi^{2}_{calc.}$ or $\chi^{2}_{calc.}>\chi^{2}_{(1-\alpha /2), (n-1)}$ .

The degrees of freedom is:

$n-1=81-1=80$

Compute the critical from a Chi-square table.

$\chi^{2}_{\alpha /2, (n-1)}=\chi^{2}_{0.05, 80}=101.879\\\chi^{2}_{(1-\alpha /2), (n-1)}=\chi^{2}_{0.95, 80}=60.391\\$

The test statistic value is, $\chi^{2}_{calc.}=105.8$ .

$\chi^{2}_{calc.}=105.8 > \chi^{2}_{0.05, 80}=101.879$

The null hypothesis is rejected because the test statistic is in the critical region.

Thus, the correct option is (a).

6 0

3 years ago

PLEASE HELP ME with this equation I’m struggling

statuscvo [17]

Answer:

describe this

Step-by-step explanation:

the first one is the one that is closest to horizontal.

8 0

3 years ago