The population of the town in 1960 is 48.80 thousands
<h3>How to determine the population in 1950?</h3>
The equation of the model is given as:
f(t) = 42e^(0.015t)
1960 is 10 years after 1950.
This means that:
t = 10
Substitute t = 10 in f(t) = 42e^(0.015t)
f(10) = 42e^(0.015 * 10)
Evaluate
f(10) = 48.80
Hence, the population of the town in 1960 is 48.80 thousands
Read more about exponential functions at:
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Option A = $15,748.096
Formula for compound interest = P(1+Interest Rate)^n
=> 14000(1.04)^3
=$15,748.096
%change=100(final-initial)/initial
%change=100(25-40)/40=-37.5%
So Denise received a discount of 37.5% off the regular price.
Answer:
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Step-by-step explanation:
