Area of square
= 7x7
=49
Area of triangle
=0.5x 7x12
=42
Total area of figure
=49+42
=91
Hence, answer is D
Answer and Step-by-step explanation:
(a) Given that x and y is even, we want to prove that xy is also even.
For x and y to be even, x and y have to be a multiple of 2. Let x = 2k and y = 2p where k and p are real numbers. xy = 2k x 2p = 4kp = 2(2kp). The product is a multiple of 2, this means the number is also even. Hence xy is even when x and y are even.
(b) in reality, if an odd number multiplies and odd number, the result is also an odd number. Therefore, the question is wrong. I assume they wanted to ask for the proof that the product is also odd. If that's the case, then this is the proof:
Given that x and y are odd, we want to prove that xy is odd. For x and y to be odd, they have to be multiples of 2 with 1 added to it. Therefore, suppose x = 2k + 1 and y = 2p + 1 then xy = (2k + 1)(2p + 1) = 4kp + 2k + 2p + 1 = 2(kp + k + p) + 1. Let kp + k + p = q, then we have 2q + 1 which is also odd.
(c) Given that x is odd we want to prove that 3x is also odd. Firstly, we've proven above that xy is odd if x and y are odd. 3 is an odd number and we are told that x is odd. Therefore it follows from the second proof that 3x is also odd.
Answer: The value of x = 1.
Step-by-step explanation: I only inputted the answer as you said. Hope this helps!
Answer:
Table C
Step-by-step explanation:
Given
Table A to D
Required
Which shows a proportional relationship
To do this, we make use of:
Where k is the constant of proportionality.
In table (A)
x = 2, y = 4
x = 4, y = 9
Both values of k are different. Hence, no proportional relationship
In table (B)
x = 3, y = 4
x = 9, y = 16
Both values of k are different. Hence, no proportional relationship
In table (C):
x = 4, y = 12
x = 5, y = 15
x = 6, y = 18
This shows a proportional relationship because all values of k are the same for this table
