Helppp meeee plzz. Thank you

A small town is electing a new town council member. They decide to poll three random samples of registered voters to get an idea

sertanlavr [38]

Answer:

Sample #1 Sample #2 Sample #3

Candidate #1 11 20 11

Candidate #2 27 23 28

Step-by-step explanation:

The town has 8,400 registered voters

8 0

3 years ago

Carrie is comparing the growth of plants under natural and artificial light sources.

Elenna [48]

Answer:

Median :

P = 2 ; Q = 3.5

Variability :

P = 1.5 ; Q = 1.5

Step-by-step explanation:

The measure of center we can infer from the box plot is the median, which is the point marked by the vertical line in between the box ;

For Group P:

Median = 2 inches

For Group Q :

Median = 3.5 inches

To infer the variability :

We calculate the interquartile range (IQR) :

IQR = Q3 - Q1

Q3 = Upper quartile (end point of box) ; Q1 = lower quartile (start point of box) in the plot

Locate QI and Q3

Group P:

IQR = Q3 - Q1 = 3 - 1.5 = 1.5

Group Q :

IQR = Q3 - Q1 = 4.5 - 3 = 1.5

8 0

3 years ago

Which shows the distributive property?

Anvisha [2.4K]

Answer:

pretty sure it would be C

7 0

3 years ago

SOMEONE PLEASE HELP ITS DUE TONIGHT<br><br> EXPLANATION = BRAINLIEST

Vaselesa [24]

Given:

Radius of the circle = 4 meters

Measure of arc = 135 degrees

To find:

The area of the sector bounded by the given arc.

Solution:

Formula for area of a sector is:

$A=\pi r^2\times \dfrac{\theta}{360^\circ}$

Where, r is the radius and $\theta$ is the central angle or measure of intercepted arc.

Putting $r=4,\ \theta =135^\circ$ in the above formula, we get

$A=\pi \times (4)^2\times \dfrac{135^\circ}{360^\circ}$

$A=\pi \times 16\times \dfrac{3}{8}$

$A=\pi \times 2\times 3$

$A=6\pi$

Therefore, the exact area of the given sector is $6\pi$ square meters.

3 0

3 years ago

3. A research study asked children which of four different emotions they associated with the color red. The response and gender

user100 [1]

Answer:

This is required solution

Step-by-step explanation:

Given that:

for male

joy = 28

happiness = 20

love = 40

anger = 18

a] we need to calculate the percentage of emotions for the male

using formula for percentage

$\percentage\ of\ emotions=\dfrac{emotion}{total\ emotions}\times100$

percentage of joy = $\dfrac{28}{106}\times100$

percentage of joy = 26.41

percentage of happiness = $\dfrac{20}{106}\times100$

percentage of happiness = 18.86

percentage of love = $\dfrac{40}{106}\times100$

percentage of love = 37.73

percentage of anger = $\dfrac{18}{106}\times100$

percentage of anger = 16.98

for female

joy = 61

happiness = 25

love = 80

anger = 60

we need to calculate the percentage of emotions for the female

using formula for percentage

$\percentage\ of\ emotions=\dfrac{emotion}{total\ emotions}\times100$

percentage of joy = $\dfrac{61}{226}\times100$

percentage of joy = 26.99

percentage of happiness = $\dfrac{25}{226}\times100$

percentage of happiness = 11.06

percentage of love = $\dfrac{80}{226}\times100$

percentage of love = 35.39

percentage of anger = $\dfrac{60}{226}\times100$

percentage of anger = 26.54

B] We need to draw a bar graph for male and female

using percentage of emotion of male and female

according to using percentage we draw a bar graph using data of part A.

Hence, this is required solution

7 0

4 years ago