Carrie is comparing the growth of plants under natural and artificial light sources.

have joined my boarding school, and writing this letter as per your demand to tell my experience.I came here about two days back. The school is eco friendly with multicoloured flowers and a field full of greenery. My hostel rooms and classrooms, both are highly ventilated and sun-facing. During these summer times, we don't need an air conditioner at all.

have joined my boarding school, and writing this letter as per your demand to tell my experience.I came here about two days back. The school is eco friendly with multicoloured flowers and a field full of greenery. My hostel rooms and classrooms, both are highly ventilated and sun-facing. During these summer times, we don't need an air conditioner at all.My classmates are good and I made few friends as well. The same is for hostel roommates too. Food too is very delicious here. We have playing time and television time as well.

have joined my boarding school, and writing this letter as per your demand to tell my experience.I came here about two days back. The school is eco friendly with multicoloured flowers and a field full of greenery. My hostel rooms and classrooms, both are highly ventilated and sun-facing. During these summer times, we don't need an air conditioner at all.My classmates are good and I made few friends as well. The same is for hostel roommates too. Food too is very delicious here. We have playing time and television time as well.Here everyone is very disciplined and strict for their routine and studies. Overall the environment is very nice here. Do write about what's going with you.

Love

(JOE or Gabriel)

HOPE THIS HELPED

8 0

2 years ago

Simplify using the distributive property. 5 Marks<br> 1/5(4m+20)<br><br> 9(5/9 y-1/3)

Zarrin [17]

Answer+Step-by-step explanation:

$\frac{1}{5} \left( 4m+20\right) =\frac{4}{5}m + \frac{20}{5} = \frac{4}{5}m + 4$

$9\left( \frac{5}{4} y-\frac{1}{3} \right) =\frac{9\times5}{9} y-\frac{9}{3} = 5y - 3$

4 0

1 year ago

1. A box contains 10 blue Stickers, 15 red stickers , and 25 orange stickers . A sticker is selected and its color noted. Then i

denis-greek [22]

Answer:

1/25 ; 3/20 ; 3/50

Step-by-step explanation:

Total number of stickers :

(10 + 15 + 25) = 50 stickers

Probability = required outcome / Total possible outcomes

a. Selecting blue and blue stickers

P(First blue) = 10/50 = 1/5

P(second blue) = 10/50 = 1/5

1/5 * 1/5 = 1 / 25

b. Selecting one red sticker and then one orange sticker

P(First red) = 15/50 = 3/10

P(second orange) = 25/50 = 1/2

3/10 * 1/2 = 3 /20

Selecting one red sticker and then one blue sticker

P(First red) = 15/50 = 3/10

P(second blue) = 10/50 = 1/5

3/10 * 1/5 = 3 / 50

4 0

2 years ago