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2 years ago

7

Please Help, I need to know how to graph these equations

1 answer:

devlian [24]2 years ago

5 0

There's a site called m.a.t.h.w.a.y, and you can type in those functions in order to get the graph ;)

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What is the distance between the points 3, 7 and 15, 6 on a coordinate plane

krok68 [10]

Answer:

$D=\sqrt{145 }\\$

Step-by-step explanation:

We are actually using Pythagorean theorem here but to be simple

we can use the equation:

D(distance)= $\sqrt{(x_{1}- x_{2} )^{2} +( y_{1}-y_{2})^{2}}$

=

$D=\sqrt{(15-3)^{2}+(6-7)^{2} } =\\D=\sqrt{(12)^{2}+(-1)^{2} } =\\\\D=\sqrt{144+1 } =\\D=\sqrt{145 }\\$

(If you meant 16 instead of 6 the answer would be 15)

Hope this helps!

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2 years ago

Set up iterated integrals for both orders of integration. Then evaluate the double integral using the easier order. y dA, D is b

Yuliya22 [10]

Answer: The answer is 183.08

Step-by-step explanation: see the picture attached

7 0

2 years ago

It's geometry please help me

Gekata [30.6K]

Answer:

x=13

Step-by-step explanation:

C is the midpoint of line BD, BC=CD. 6x-16=4x+10, x=13

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2 years ago

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jeka57 [31]

Idk the answer tether

4 0

2 years ago

Find the value of tan( π + θ) if θ terminates in Quadrant III and sinθ = -5/13

Vladimir79 [104]

ANSWER

$\tan(\pi + \theta)= \frac{5}{12}$

EXPLANATION

We first obtain

$\cos( \theta)$

using the Pythagorean Identity.

$\cos ^{2} ( \theta) + \sin ^{2} ( \theta) = 1$

$\implies \: \cos ^{2} ( \theta) + ( - \frac{5}{13} )^{2} = 1$

$\implies \: \cos ^{2} ( \theta) + \frac{25}{169}= 1$

$\implies \: \cos ^{2} ( \theta) = 1 - \frac{25}{169}$

$\implies \: \cos ^{2} ( \theta) = \frac{144}{169}$

$\implies \: \cos ( \theta) = \pm \: \sqrt{\frac{144}{169} }$

$\implies \: \cos ( \theta) = \pm \: \frac{12}{13}$

In the third quadrant, the cosine ratio is negative.

$\implies \: \cos ( \theta) = - \: \frac{12}{13}$

The tangent function has a period of π and $\pi + \theta$ is in the third quadrant.

This implies that:

$\tan(\pi + \theta)= \tan( \theta)$

$\tan(\pi + \theta)= \frac{ \sin( \theta) }{ \cos( \theta) }$

$\tan(\pi + \theta)= \frac{ - \frac{ 5}{13} }{ - \frac{12}{13} }$

This gives us:

$\tan(\pi + \theta)= \frac{5}{12}$

8 0

3 years ago