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Aliun [14]
3 years ago
8

Solve for f (-3) for f (x) = 1 -x f (-3) = [ ? ]

Mathematics
2 answers:
Lostsunrise [7]3 years ago
3 0
F(x) = 1 - x
f(-3) = 1 - (-3)
f(-3) = 4
Xelga [282]3 years ago
3 0
f(-3) = 1 -(-3) = 1+3 = 4

Hope this helps !

Photon
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What is the slope of the line that passes through the points (-10, -8) and
bazaltina [42]
First of all we have to find the slope


m = y₂-y₁ / x₂-x₁

m = -8 + 16 / -10 + 8

m = 8/-2

m = -4

y-y₁ = m (x-x₁)

y + 8 = -4 (x + 10)

y + 8 = -4x - 40

y = -4x -40 - 8

y = -4x -48
7 0
3 years ago
⦁ Show (2.3)(5.06) as a fraction multiplication problem and explain why the answer is in thousandths (three decimal places). 
astra-53 [7]

we have

(2.3)(5.06)

we know that

2.3=\frac{23}{10}

5.06=\frac{506}{100}

so

(2.3)(5.06)=(\frac{23}{10})(\frac{506}{100})

=\frac{11,638}{1,000}

=11.638

the answer is in thousandths, because the denominator of the multiplication of the two fractions is one thousand

8 0
3 years ago
Read 2 more answers
Is (2, 2) a solution of y < 4x – 6?
Roman55 [17]

Answer:

No

Step-by-step explanation:

To see if (2,2) is a solution, substitute them into the inequality and see if it is true.

2 is our x value, and 2 is also our y value

y < 4x – 6

2< 4(2)– 6

2 < 8 – 6

2 < 2

This statement is false. 2 is not less than 2, so (2,2) is not a solution to this equation.

6 0
3 years ago
Express the quotient of z1 and z2 in standard form given that <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D%20-3%5Bcos%28%5C
Lesechka [4]

Answer:

Solution : -\frac{3}{4}-\frac{3}{4}i

Step-by-step explanation:

-3\left[\cos \left(\frac{-\pi }{4}\right)+i\sin \left(\frac{-\pi \:}{4}\right)\right]\:\div \:2\sqrt{2}\left[\cos \left(\frac{-\pi \:\:}{2}\right)+i\sin \left(\frac{-\pi \:\:\:}{2}\right)\right]

Let's apply trivial identities here. We know that cos(-π / 4) = √2 / 2, sin(-π / 4) = - √2 / 2, cos(-π / 2) = 0, sin(-π / 2) = - 1. Let's substitute those values,

\frac{-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)}{2\sqrt{2}\left(0-1\right)i}

=-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right) ÷ 2\sqrt{2}\left(0-1\right)i

= 3\left(-\frac{\sqrt{2}i}{2}+\frac{\sqrt{2}}{2}\right) ÷ -2\sqrt{2}i

= \frac{3\left(1-i\right)}{\sqrt{2}}÷ 2\sqrt{2}i = -3-3i ÷ 4 = -\frac{3}{4}-\frac{3}{4}i

As you can see your solution is the last option.

3 0
3 years ago
Draw a picture to show how to find12+37
Karolina [17]
So i drew 12 circles and 37 circles
And i got 49 total:D 
i hope this helps and sorry that the pic is wierd:(


7 0
3 years ago
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