First of all we have to find the slope
m = y₂-y₁ / x₂-x₁
m = -8 + 16 / -10 + 8
m = 8/-2
m = -4
y-y₁ = m (x-x₁)
y + 8 = -4 (x + 10)
y + 8 = -4x - 40
y = -4x -40 - 8
y = -4x -48
we have

we know that


so



the answer is in thousandths, because the denominator of the multiplication of the two fractions is one thousand
Answer:
No
Step-by-step explanation:
To see if (2,2) is a solution, substitute them into the inequality and see if it is true.
2 is our x value, and 2 is also our y value
y < 4x – 6
2< 4(2)– 6
2 < 8 – 6
2 < 2
This statement is false. 2 is not less than 2, so (2,2) is not a solution to this equation.
Answer:
Solution : 
Step-by-step explanation:
![-3\left[\cos \left(\frac{-\pi }{4}\right)+i\sin \left(\frac{-\pi \:}{4}\right)\right]\:\div \:2\sqrt{2}\left[\cos \left(\frac{-\pi \:\:}{2}\right)+i\sin \left(\frac{-\pi \:\:\:}{2}\right)\right]](https://tex.z-dn.net/?f=-3%5Cleft%5B%5Ccos%20%5Cleft%28%5Cfrac%7B-%5Cpi%20%7D%7B4%7D%5Cright%29%2Bi%5Csin%20%5Cleft%28%5Cfrac%7B-%5Cpi%20%5C%3A%7D%7B4%7D%5Cright%29%5Cright%5D%5C%3A%5Cdiv%20%5C%3A2%5Csqrt%7B2%7D%5Cleft%5B%5Ccos%20%5Cleft%28%5Cfrac%7B-%5Cpi%20%5C%3A%5C%3A%7D%7B2%7D%5Cright%29%2Bi%5Csin%20%5Cleft%28%5Cfrac%7B-%5Cpi%20%5C%3A%5C%3A%5C%3A%7D%7B2%7D%5Cright%29%5Cright%5D)
Let's apply trivial identities here. We know that cos(-π / 4) = √2 / 2, sin(-π / 4) = - √2 / 2, cos(-π / 2) = 0, sin(-π / 2) = - 1. Let's substitute those values,

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As you can see your solution is the last option.
So i drew 12 circles and 37 circles
And i got 49 total:D
i hope this helps and sorry that the pic is wierd:(