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Aliun [14]
3 years ago
8

Solve for f (-3) for f (x) = 1 -x f (-3) = [ ? ]

Mathematics
2 answers:
Lostsunrise [7]3 years ago
3 0
F(x) = 1 - x
f(-3) = 1 - (-3)
f(-3) = 4
Xelga [282]3 years ago
3 0
f(-3) = 1 -(-3) = 1+3 = 4

Hope this helps !

Photon
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The product of two numbers is 48. The first number is negative, and the second number is four more than twice the first number.
aksik [14]
First number is a and second one is 2a+4
a(2a+4)=48
a(a+2)=24
a^2+2a-24=0
(a+6)(a-4)=0
the question says a is negative so a=-6 b=-8
3 0
3 years ago
What would the answer be for this equation 7x/20 - 5x/12
polet [3.4K]

Answer:

\frac{1}{15} x

Step-by-step explanation:

\frac{7x}{20}  -  \frac{5x}{12}

\frac{3 \times 7x}{3 \times 20}  -  \frac{5 \times 5x}{5 \times 12}

\frac{21x}{60}  -  \frac{25x}{60}

\frac{21x - 25x}{60}  = (21 - 25)x =  - 4x

\frac{ - 4x}{60}  =  -  \frac{ x}{15}

\boxed{\green{=  \frac{1}{15} x}}

4 0
2 years ago
Select the term that best describes the statement A triangle is acute provided all the angles have a measure of less than 90 deg
Burka [1]
I think the correct answer is conjunction...
3 0
3 years ago
Four root of five<br><img src="https://tex.z-dn.net/?f=4%20%5Csqrt%7B5%20%3D%20%7D%20" id="TexFormula1" title="4 \sqrt{5 = } " a
Georgia [21]

Answer:

8.94427191

:)

Step-by-step explanation:

7 0
3 years ago
Community college students conduct a survey at their college. They ask "Do you plan to transfer to a university to pursue a bacc
Tamiku [17]

Answer:

0.8 - 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.697

0.8 + 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.903

The 99% confidence interval would be given by (0.697;0.903)

And the best option is : 0.697 to 0.903

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

For this case the conditions we have the conditions to assume a normal distribution for the population proportion since:

np=100*0.8=80 >10 , n(1-p) = 10*(1-0.8) =20 >10

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

The estimated proportion is given by \hat p =\frac{80}{100} =0.8. If we replace the values obtained we got:

0.8 - 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.697

0.8 + 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.903

The 99% confidence interval would be given by (0.697;0.903)

And the best option is : 0.697 to 0.903

6 0
2 years ago
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