Answer: (2, 5)
Step-by-step explanation:
y = 2x + 1 y = 4x − 3
Eliminate the equal sides of each equation and combine.
2x + 1 = 4x − 3
Solve 2x + 1 = 4x − 3 for x.
Move all terms containing x to the left side of the equation.
Subtract 4x from both sides of the equation.
2x + 1 − 4x = −3
Subtract 4x from 2x.
−2x + 1 = −3
Move all terms not containing x to the right side of the equation.
Subtract 1 from both sides of the equation.
−2x = −3 − 1
Subtract 1 from −3.
−2x = −4
Divide each term by −2 and simplify.
x = 2
Evaluate y when x = 2.
Substitute 2 for x. y = 4 (2) − 3
Simplify 4 (2) − 3.
Multiply 4 by 2.
y = 8 − 3
Subtract 3 from 8.
y = 5
The solution to the system is the complete set of ordered pairs that are valid solutions.
(2, 5)
The result can be shown in multiple forms.
Point Form:
(2, 5)
Equation Form:
x = 2, y = 5
Area of the figure is 171 cm²
See the attachment......
Answer:
No Solution.
Step-by-step explanation:
-6(x-7)+6(x+5)=73
-6x+42+6x+30=73
72=73
no solution
9514 1404 393
Answer:
(b) 7720 mm² of paper
Step-by-step explanation:
The central horizontal rectangle of the net is 80 mm high and ...
40 + 5.5 + 40 + 5.5 = 91
mm long. Its area 9 is ...
(80 mm)(91 mm) = 7280 mm²
__
The two pieces of the net not accounted for above are the "flaps" above and below the central rectangle. Each of those two has an area of 40 mm by 5.5 mm, so their total area is ...
2(40 mm)(5.5 mm) = 440 mm²
Then the area of paper needed for the wrapper is ...
total area = 7280 mm² + 440 mm²
total area = 7720 mm²
1/2:5
1:10
2:20
The actual length of the room is 20 feet.