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Zanzabum
3 years ago
10

Evaluate using the order of operations. 54 + (9.2 - 1.413)

Mathematics
1 answer:
Step2247 [10]3 years ago
5 0
The answer is 61.787 

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There is a number such that four times the number plus 3 is equal to 19. Find the number
frosja888 [35]

Answer:

4

Step-by-step explanation:

We have been given that it equals 19 when added to 3 and multiplied by 4 so follow these steps:

1. set the equation 4x+3=19

2. solve for x

4x+3-3=19-3

This is used to solve for x

3. 4x=16 is found

4. if 4x=16, we divide 16/4 and get 4!

That's your answer hope it helped!

3 0
4 years ago
Read 2 more answers
Which of the following is a linear function?
olga55 [171]

Answer:

Which of the following is a linear function?

  1. y = x^3 + 1
  2. (5/6)x = y − 4
  3. y = 8x^2
  4. y =(1/5)x

<u>2. (5/6)x = y − 4 and 4. y =(1/5)x</u> are the right answers.

Step-by-step explanation:

Linear function is in the form <u>y=ax+b</u><u>.</u>

8 0
3 years ago
You flip a coin twice. The first flip lands
Slav-nsk [51]

Answer:

Step-by-step explanation:

Should be 2/2

8 0
4 years ago
Read 2 more answers
.<br> What is the greatest common monomial factor of 8c 3m 5 + 24c 2m 3 ?
Semmy [17]

Answer:

GCF is the greatest common factor of two or more terms or values. The GCF must be a factor of each term, meaning both terms must be divisible by the GCF. A monomial is a single term within an algebraic expression. It can be a number, variable, or a product of a number and variables, and any exponents of variables must be whole numbers (0, 1, 2, 3, ...). Examples include: 33, 3x3x, xyzxyz, and 2x2y3z22x2y3z2.

8 0
3 years ago
Let x be a discrete random variable that possesses a binomial distribution with n=5 and p=0.87. What are the mean and standard d
Nookie1986 [14]

Answer:

Mean = 4.35

SD = 0.5655

Step-by-step explanation:

Given

n = 5

p = 0.87

Solving (a): Mean

Mean = np

Mean = 5 * 0.87

Mean = 4.35

Solving (b): Standard Deviation (SD)

SD = np(1 - p)

SD = 5 * 0.87(1 - 0.87)

SD = 5 * 0.87 * 0.13

SD = 0.5655

4 0
4 years ago
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