Answer:
none
Step-by-step explanation:
We are given a triangle ABC with ∠A = 30°, sides a = 4 and b = 10.
According to the 'Law of Sines- Ambiguous Case', we have,
If a < b×sinA, then no triangle is possible.
If a = b×sinA, only one triangle is possible
If a > b×sinA, two triangles are possible.
So, we have,
b×sinA = 10 × sin30 = 10 × 0.5 = 5.
Now, as
4 = a < bsinA = 5.
We get, according to the rule, no triangle is possible.
Answer:
use the distributive property to distribute the 8
-16+16n+3n=40+5n
-16+19n=40+5n
-16=40+5n-19n
-16=40-14n
-14n+40= -16
-14n= -16-40
-14n= -56
n= -56/-14
n= 4
Answer:
3 games
Step-by-step explanation:
The computation of the maximum number of games that he could buy is shown below:
= Amount available - already spent
= $75 - $28
= $47
If each game cost $15
So, the maximum no of games is
= $47 ÷ $15
= 3.133
= 3 games
2 * 10^2
Divide the first numbers, which are 6 and 3, to get 2. Then, subtract the powers of the exponents, which are 5 and 3, to get 2.
Answer:
A= 21 m
Step-by-step explanation:
