Graph the function. y = 2x^2 + 4x

Mathematics

1 answer:

rodikova [14]2 years ago

3 0

Answer:

Step-by-step explanation:

The function y = 2x^2 + 4x has a parabolic graph that opens up.

*In factored form we have y = 2x(x + 2); if we set this equal to zero and solve for x, we obtain {-2, 0}, the roots of this function.

*The axis of symmetry is halfway between these roots: x = -1. The y-value of the vertex is the value of the function at x = -1: f(-1) = 2(-1)^2 + 4(-2) = -6. Thus, the vertex is (-1, -6).

* The y-intercept is (0, 0), since y = 0 when x = 0.

Graph the points shown and draw a smooth curve through them, remembering that this parabola opens up.

You might be interested in

A jacuzzi that holds 250 gallons of water drains at a rate of 9 gallons per minute. Write an equation that represents how many g

ki77a [65]

Step-by-step explanation:

Amount of water left = 250 - 9x.

6 0

3 years ago

HELP NEED FAST!!!!!! Which graph shows a negative slope and a positive y-intercept?

jekas [21]

Answer:

the second one on the top right

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Which of the following is the solution to the differentiable equation dy/dx=4x/y, where Y(2)=-2

cupoosta [38]

Answer:

b is the answer

Step-by-step explanation:

7 0

3 years ago

What is the measure of this angle?

meriva

Answer: D. 170

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Can I get help solving this graph please?

Daniel [21]

see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100) B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40) C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0) B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60) C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find h'(x)
h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x)
h'(x)=18/25=0.72

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

 h'(x) = 1.44 ------------ > not exist

8 0

3 years ago