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4 years ago

15

20 out of 45 students attend the concert;12 out of 25 students attend the concert

1 answer:

svetlana [45]4 years ago

7 0

13 students went to the concert

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Use the quadratic formula to find the solutions to the quadratic equation below x^2-6x-5=0

Sonja [21]

Answer:

$\large\boxed{x=3-\sqrt{14}\ \vee\ x=3+\sqrt{14}}$

Step-by-step explanation:

$x^2-6x-5=0\qquad\text{add 5 to both sides}\\\\x^2-6x=5\\\\x^2-2(x)(3)=5\qquad\text{add}\ 3^2\ \text{to both sides}\\\\x^2-2(x)(3)+3^2=5+3^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\(x-3)^2=5+9\\\\(x-3)^2=14\to x-3=\pm\sqrt{14}\qquad\text{add 3 to both sides}\\\\x=3-\sqrt{14}\ \vee\ x=3+\sqrt{14}$

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3 years ago

"The product of two numbers is 169. If the L.C.M. of these numbers is 13, find their H.C.F. "

umka21 [38]

Answer:

13

Step-by-step explanation:

HCF = Product of two numbers ÷ LCM of these numbers

HCF = $\frac{169}{13}$

= 13

3 0

3 years ago

A 10-yr-old competes in gymnastics. For several competitions, she received the following "All-Around" scores: 35.5, 36.3. 36.6,

Delicious77 [7]

Answer:

The child needs a score of 37.2 to move up to the next level of the competition.

Step-by-step explanation:

The mean is the sum of all scores divided by the number of competions. So

$M = \frac{S}{T}$

In which S is the sum of all her scores and T is the number of competitions.

The child has five competions:

Which means that $T = 5$

She has to get a mean of at least 36.5, so $M = 36.5$

Her scores are: 35.5, 36.3. 36.6, and 36.9. Her last score, i am going to call x. So

$S = 35.5 + 36.3 + 36.6 + 36.9 + x = 145.3 + x$

The child needs a score of _____ to move up to the next level of the competition.

This score is x. So

$M = \frac{S}{T}$

$36.5 = \frac{145.3 + x}{5}$

$145.3 + x = 36.5*5$

$x = 37.2$

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3 years ago

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tekilochka [14]

Answer:

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