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tresset_1 [31]
2 years ago
8

Can someone please help me with this square root problem?

Mathematics
1 answer:
nadya68 [22]2 years ago
4 0

Answer:

x=14.87

Step-by-step explanation:

What we want to use is pythagoras theorem:

a^2+b^2=c^2, where c is the hypotenuse

10^2+11^2=x^2

221=x^2

x=\sqrt{221}

x=14.866...

x=14.87

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leva [86]

Looks like the equation is

yy'+x=\sqrt{x^2+y^2}

Substitute u(x)=x^2+y(x)^2, so that u'=2x+2yy'. Then the equation is the same as

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Answer:

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2 years ago
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