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LUCKY_DIMON [66]
3 years ago
13

Need help with this data table need it to end up to 1024 thanks

Mathematics
1 answer:
Iteru [2.4K]3 years ago
3 0
1 2 4 8 16 32 64 128 256 512 1024. each one is 2 times the previous

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Can you please answer
BabaBlast [244]
I believe it should be A.
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3 years ago
John O'Sullivan has just completed his first year in business. His records show that he spent the following in advertising: Inte
krek1111 [17]

Answer:

29.787%

Step-by-step explanation:

The computation of the percentage that spend on yellow pages is shown below:

= Yellow pages ÷ Total advertising cost

= $700 ÷ ($700 + $600 + $650 + $400)

= $700 ÷ $2,350

= 29.787%

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3 years ago
4^4x-5= 8^3x-4 solve
Alexxandr [17]

4^{4x-5}=8^{3x-4}\\\\(2^2)^{4x-5}=(2^3)^{3x-4}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\2^{2(4x-5)}=2^{3(3x-4)}\iff2(4x-5)=3(3x-4)\qquad\text{use distributive property}\\\\(2)(4x)+(2)(-5)=(3)(3x)+(3)(-4)\\\\8x-10=9x-12\qquad\text{add 10 to both sides}\\\\8x=9x-2\qquad\text{subtract 9x from both sides}\\\\-x=-2\to \boxed{x=2}

8 0
3 years ago
WILL GIVE BRAINLIEST
ludmilkaskok [199]

Answer:

Air that is moving primarily in a horizontal direction.

8 0
3 years ago
Read 2 more answers
What is the product?
ZanzabumX [31]

Answer:

The product is:

\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]

Step-by-step explanation:

For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:

\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]

1 \times 2 + 3 \times 3 + 1 \times -2 = 15

So the value of the element in the position a_{11} is 15

1 \times -2 + 3 \times 5 + 1 \times 1 = 14

So the value of the element in the position a_{12} is 14

Then with these two values you can determinate the result matrix.

\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]

3 0
2 years ago
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