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dalvyx [7]
2 years ago
8

Elliot ran 4 laps in 209.2 seconds. If he ran at the same

Mathematics
1 answer:
ASHA 777 [7]2 years ago
6 0

Answer: 52.3 seconds

Step-by-step explanation:

209.2 divided by 4

which is 52.3 seconds

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4. Find a pair of irrational numbers whose product is an integer.
nataly862011 [7]

Answer:

√2 and √3

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
You have to evaluate<br> 3³+11-10÷2×4=w
denis23 [38]

Answer:

18

<u><em>Brainliest, please!</em></u>

Step-by-step explanation:

3^3 + 11 - 10 / 2 x 4 = w

27 + 11 - 10 / 2 x 4 = w

27 + 11 - 5 x 4 = w

27 + 11 - 20 = w

38 - 20 = w

w = 18

3 0
3 years ago
I need help this is 7th grade homework
Alla [95]
Number of weeks in a year divided by 6, then multiply that answer by $108
8 0
3 years ago
Pleaseee helppp with thissss asapppp
Natasha2012 [34]

As we know that the standard equation of circle is {\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}} , where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>

Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively

{:\implies \quad \sf \{2-(-1)\}^{2}+(9-5)^{2}=r^{2}}

{:\implies \quad \sf (3)^{2}+(4)^{2}=r^{2}}

{:\implies \quad \sf 9+16=r^{2}}

After raising ½ power to both sides , we will get <em>r = +5 , -5</em> , but as radius can never be -<em>ve</em> . So <em>r = +</em><em>5</em><em> </em>

Now , putting values in our standard equation ;

{:\implies \quad \sf \{x-(-1)\}^{2}+(y-5)^{2}=(5)^{2}}

{:\implies \quad \bf \therefore \quad \underline{\underline{(x+1)^{2}+(y-5)^{2}=25}}}

<em>This is the required equation of </em><em>Circle</em>

Refer to the attachment as well !

8 0
2 years ago
-(6)^-1<br> a.6<br> b.1/6<br> c.-1/6<br> d.-6<br><br> No idea what I'm doing...
Monica [59]
-(6)^{-1} = ?
<span>Representing in fraction for the best understanding
</span>-(\frac{6}{1}) ^{-1} = ?<span>
When the exponent is negative, the inversion is made, the numerator becomes the denominator, and the denominator becomes the numerator, and the change of signal from the exponent, which was negative, becomes positive.

</span>-( \frac{1}{6} )^1 =
\boxed{\boxed{- \frac{1}{6}}}\end{array}}\qquad\quad\checkmark

Answer:
c.-1/6
7 0
2 years ago
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