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3 years ago

Please help me i don’t know if I’m right

Mathematics

1 answer:

Scilla [17]3 years ago

5 0

Answer:

your choice is correct

Step-by-step explanation:

The magnitude of the difference between the target amount and the actual amount will be no greater than the allowed error.

|x -34| ≤ 0.25

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The what of a figure is a measurement of the space inside it

Elena-2011 [213]

Answer: It would be area, because it involves multiplying length by width, therefore covering the inside

Step-by-step explanation:

3 0

3 years ago

A backpack that normally sells for $39 is on sale for 30% off. Find the amount of the sale price

andrey2020 [161]

Answer:

26.13 sale price discount 12.87

Step-by-step explanation:

I do not know how to explain it to where you will understand it but the sale price is 26.13 and the discount it 12.87

Hope that helps

8 0

3 years ago

Solving separable differential equation DY over DX equals xy+3x-y-3/xy-2x+4y-8

Ivanshal [37]

It looks like the differential equation is

$\dfrac{dy}{dx} = \dfrac{xy + 3x - y - 3}{xy - 2x + 4y - 8}$

Factorize the right side by grouping.

$xy + 3x - y - 3 = x (y + 3) - (y + 3) = (x - 1) (y + 3)$

$xy - 2x + 4y - 8 = x (y - 2) + 4 (y - 2) = (x + 4) (y - 2)$

Now we can separate variables as

$\dfrac{dy}{dx} = \dfrac{(x-1)(y+3)}{(x+4)(y-2)} \implies \dfrac{y-2}{y+3} \, dy = \dfrac{x-1}{x+4} \, dx$

Integrate both sides.

$\displaystyle \int \frac{y-2}{y+3} \, dy = \int \frac{x-1}{x+4} \, dx$

$\displaystyle \int \left(1 - \frac5{y+3}\right) \, dy = \int \left(1 - \frac5{x + 4}\right) \, dx$

$\implies \boxed{y - 5 \ln|y + 3| = x - 5 \ln|x + 4| + C}$

You could go on to solve for $y$ explicitly as a function of $x$ , but that involves a special function called the "product logarithm" or "Lambert W" function, which is probably beyond your scope.

8 0

2 years ago

Estes Park Corp. pays a constant $6.95 dividend on its stock. The company will maintain this dividend for the next 12 years and

Brrunno [24]

The present value of an annuity of n periodic payments of P at r% where payment is made annually is given by:

$PV=P \left[\frac{1-(1+r)^{-n}}{r} \right]$

Given that Estes Park Corp. pays a constant dividend of P = $6.95 on its stock. The company will maintain this dividend for the next n = 12 years and will then cease paying dividends forever. If the required return on this stock is r = 10 % = 0.1.

Thus, the current share price is given by:

$Current \ share \ price=6.95 \left[\frac{1-(1+0.1)^{-12}}{0.1} \right] \\ \\ =6.95\left[\frac{1-(1.1)^{-12}}{0.1} \right] =6.95\left(\frac{1-0.3186}{0.1} \right)=6.95\left(\frac{0.6814}{0.1} \right) \\ \\ =6.95(6.813)=\bold{\$47.36}$

Therefore, the current share price is $47.36

5 0

3 years ago

Suppose a random variable, x, arises from a binomial experiment. If n = 6, and p = 0.30, find the following probabilities using

AlladinOne [14]

Answer:

a) P(X=1) = 0.302526

b) P(X=5) = 0.010206

c) P(X=3) = 0.18522

d) P(X≤3) = 0.92953

e) P(X≥5) = 0.010935

f) P(X≤4) = 0.989065

Explanation:

Binomial experiments are modeled by the formula:

$P(X=x)=C(n,x)\cdot p^x\cdot (1-p)^{(n-x)}$

Where

P(X=x) is the probability of exactly x successes

$C(n,x)=\dfrac{n!}{x!\cdot (n-x)!}$

p is the probability of one success, which must be the same for every trial, and every trial must be independent of other trial.

n is the number of trials

1 - p is the probability of fail

there are only two possible outcomes for each trial: success or fail.

a.) P (x=1)

$P(X=1)=\dfrac{6!}{1!\cdot (6-1)!}\times (0.3)^1\times(1-0.3)^{(6-1)}=0.302526$

b.) P (x=5)

$P(X=5)=\dfrac{5!}{5!\cdot (6-5)!}\times (0.3)^5\times (1-0.3)^{(6-5)}=0.010206$

c.) P (x=3)

Using the same formula:

$P(X=3)=0.18522$

d.) P (x less than or equal to 3)

P(X≤3)= P(X=3) + P(X=2) + P(X=1) + P(X=0)

Also,

P(X≤3) = 1 - P(X≥4) = 1 - P(X=4) - P(X=5) - P(X=6)

You can use either of those approaches. The result is the same.

Using the second one:

P(X=4) = 0.059335
P(X=5) = 0.010206
P(X=6) = 0.000729

P(X≤3) = 1 - 0.05935 - 0.010206 - 0.000729 = 0.92953

e.) P(x greather than or equal to 5)

P(X≥5) = P(X=5) + P(X=6)

P(X≥5) = 0.010206 + 0.000729 = 0.010935

f.) P(x less than or equal 4)

P(X≤4) = 1 - P(X≥5) = 1 - P(X=5) - P(X=6)

P(X≤4) = 1 - 0.010206 - 0.000729 = 0.989065

5 0

3 years ago