OK????????????????????????????
The geometric rule for the nth term of the geometric sequence for which a1 =−6 and a5=−486 is -6 × 3^(n - 1)
<h3>The nth term of a geometric sequence</h3>
First term, a1 = -6
Fifth term, a5 = -486
a5 = ar^(n - 1)
-486 = -6 × r^(5-1)
-486 = -6r⁴
r⁴ = -486 / 6
r⁴ = 81
r = 4√81
r = 3
Geometric rule:
nth term = ar^(n-1)
nth term = -6 × 3^(n - 1)
Learn more about geometric sequence:
brainly.com/question/24643676
#SPJ1
Let's see what we can get by dividing 625 by 5, as it ends with a 5:
625/5 = 125
So we have 5 as one of our factors. Let's divide again by 5:
125/5 = 25
Our current prime factors now are 5 and 5, but we aren't finished. Divide again by 5:
25/5 = 5
Now we know that the prime factorization of 625 is 5 * 5 * 5 * 5, which can also be shown as 5⁴.
1.2 is less than 1.5
If you cancel out 1 from both numbers you're left with .2 and .5
Multiply both by 10 and get 2 and 5.
Obviously 2 is less than 5.
