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maksim [4K]
3 years ago
6

if you take a dried out white rose and place the stem in food coloring, will the rose turn the color you put the stem in

Chemistry
1 answer:
cricket20 [7]3 years ago
7 0

Answer:

Yes, this is true. The reason is that the flower transpires and sucks the water in and distributes it as much as it can. You can also flip it upside down and hang it with petals down , allowing the liquid to enter the flower and then retaining color for longer periods of time and having more color.

Explanation:

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Smog is the term used to describe the combination of fog and smoke
Bond [772]

Yes, it is. That is correct.

3 0
3 years ago
If 140. mg of fluorine-18 is shipped at 8:00 A.M., how many milligrams of the radioisotope are still active when the sample arri
Aleonysh [2.5K]

<u>Answer:</u>

<em>To answer the question we need to know the half-life of fluorine for reference we have chlorine half-life as 110. The fraction of chlorine remaining would be given by 0.5^n </em>

<u>Explanation:</u>

Here we know and is known as the number of Half-life that have elapsed during this process  Now we are giving the time of start as 8 a.m. and time of finishing at 1:30 p.m., so the time between is 5 ½  hours. Which on converting in minutes will give 330 minutes.

So Half Life elapsed would be given by = 330/110=3

Hence the amount remaining would be = 0.5 ^3 \times 125 =15.625

8 0
4 years ago
Read 2 more answers
The density of osmium ( the densest metal) is 22.57 g/cm^3. What volume would be occupied by 1.50 kg of osmium.
Westkost [7]

Answer:

Density = Mass / Volume

V = 1.00 * 4.00 * 2.50 = 10 cm³

22.57 g/cm³ = Mass / 10 cm³

M = 22.57 g/cm³ * 10 cm³

M = 225.7 g

Answer: The mass of the block of osmium is 225.7 g.

Explanation:

Thanks to:

HomertheGenius

5 0
3 years ago
A stock solution of HNO3 is prepared and found to contain 13.5 M of HNO3. If 25.0 mL of the stock solution is diluted to a final
salantis [7]

Answer : The correct option is, (C) 0.675 M

Explanation :

Using neutralization law,

M_1V_1=M_2V_2

where,

M_1 = concentration of HNO_3 = 13.5 M

M_2 = concentration of diluted solution = ?

V_1 = volume of HNO_3 = 25.0 ml  = 0.0250 L

conversion used : (1 L = 1000 mL)

V_2 = volume of diluted solution = 0.500 L

Now put all the given values in the above law, we get the concentration of the diluted solution.

13.5M\times 0.0250L=M_2\times 0.500L

M_2=0.675M

Therefore, the concentration of the diluted solution is 0.675 M

8 0
3 years ago
NEED ASAP WILL MARK BRAINLIEST ON TIMER
oksian1 [2.3K]
I think the answer is 1.31m

hope this helps :)
4 0
3 years ago
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