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eimsori [14]
3 years ago
9

Pure titanium metal is produced by reaction titanium(IV) chloride with magnesium metal. The equation for the reaction is: TiCl4(

s) + 2Mg(s) → 2MgCl2(s) + Ti(s) How many grams of Mg would be needed to produce 1.00 kg of pure titanium?
Chemistry
1 answer:
qaws [65]3 years ago
7 0

Answer:

The answer to your question is 1.013 Kg

Explanation:

                     TiCl₄  +  2Mg   ⇒     2MgCl₂   +   Ti

mass of Mg = ?

mass of Ti = 1 kg

Process

1.- Calculate the molar mass of Magnesium and titanium (IV)

    Mg = 24.3 g x 2 = 48.6 g

    Ti = 48 g

2.- Write a proportion (rule of three)

                         48.6 g of Mg -------------  48 g of Ti

                           x                   -------------  1000 g of Ti

                           x = (1000 x 48.6) / 48

3.- Result

                 mass of Magnesium = 1012.5g

                                                    = 1.013 kg      

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In first place, the balanced reaction is:

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By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

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The following rule of three can be applied: if by reaction stoichiometry 1 mole of C₃H₈ form 3 moles of CO₂, 0.080 moles of C₃H₈ form how many moles of CO₂?

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The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

<h3>Volume of CO₂ produced</h3>

You can apply the following rule of three: If by definition of STP 1 mole of CO₂ occupies 22.4 L, 0.24 moles of CO₂ how much volume does it occupy?

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