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Irina18 [472]
3 years ago
13

Bond energies do not account for the energy associated with the formation of aqueous solutions. Explain what energy is not accou

nted for AND how this energy contributes to the difference in calculated ∆Hrxn values using ∆Hf versus bond energy data ( -524 kJ/mol bond energy and -162.59 kJ/mol ∆Hf)
Chemistry
1 answer:
Tems11 [23]3 years ago
5 0

Answer:

Why do we all not know the answer to this on the practical

Explanation:

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What is a characteristic of asexual reproduction?
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Answer:

Sexual reproduction

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3 years ago
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What is the net amount of energy released when one mole of h2o(?) is produced?
german
The net amount of energy produced can be obtained from a table of enthalpy change of formation, available online.

The enthalpy change of formation indicate how much energy the 1 mole of the product (H2O) has relative to the elemental reactants (H2 and O2).  In other words, the "lost" energy equals the heat/energy released. 

For water (H2O), this value is -285.8 if the final product is a liquid under standard conditions, and -241.82 if the product is in gas form which contains some energy that could be further released.  This means that if the final product (H2O) is in liquid form, energy released is 285.8 kJ/mol.

Since water is in liquid form under standard conditions, the first value (285.8 kJ/mol) is generally appropriate.
7 0
3 years ago
) Calculate the number of moles of sulfuric acid that is contained in 250 mL of 0.500 M sulfuric acid solution
maksim [4K]

Explanation:

According to the analysis, Molarity is amount mole per volume(1L). the amount in mole would be molarity × volume in litres.

0.500M × (250/1000)L= 0.125moles.

I hope this helps**

3 0
3 years ago
Help please its science
Nookie1986 [14]

Answer: any answer choices

Explanation:

6 0
3 years ago
What is the boiling point of 0.464 m lactose in water? (Kb of water = 0.512 oC/m). Enter your answer to 3 decimal places.
kirill [66]

Answer:

Boiling point for the solution is 100.237°C

Explanation:

We must apply colligative property of boiling point elevation

T° boiling solution - T° boiling pure solvent = Kb . m

m = molalilty (a given data)

Kb = Ebulloscopic constant (a given data)

We know that water boils at 100°C so let's replace the information in the formula.

T° boiling solution - 100°C = 0.512 °C/m . 0.464 m

T° boiliing solution = 0.512 °C/m . 0.464 m + 100°C → 100.237 °C

3 0
3 years ago
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