<span>4 Al + 3 O2 → 2 Al2O3
(10.0 g Al) / (26.98154 g Al/mol) = 0.37062 mol Al
(19.0 g O2) / (31.99886 g O2/mol) = 0.59377 mol O2
0.37062 mole of Al would react completely with 0.37062 x (3/4) = 0.277965 mole of O2, but there is more O2 present than that, so O2 is in excess.
((0.59377 mol O2 initially) - (0.277965 mol O2 reacted)) x (31.99886 g O2/mol) =
10.1 g O2 left over</span><span>
</span>
Answer:
its caused by the convection of air masses with differences in densities mainly due to their differences in temperatures.
-Hops
Explanation:
using Boyles law: which shows the relationship between pressure and volume, when temperature Is kept constant
P1V1 = P2V2
2 x 7.2 = 0.5 x V2
14.4 = 0.5 x V2
V2 = 14.4/0.5 = 28.8 L
Hence the new size of the balloon in litres is 28.8
The given reaction is a combustion reaction, since a hydrocarbon is burning in presence of oxygen
