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igor_vitrenko [27]
3 years ago
10

Starting from methyl acetoacetate and any other necessary reagents, complete the most efficient three-step synthesis of the keto

ne, 3-benzyl-5-methylhexan-2-one, by dragging the appropriate compound(s) into the boxes. only one set of reagents will fit into each box, and all compounds will not be used.\
Chemistry
1 answer:
damaskus [11]3 years ago
3 0
Co2 is correct buddy
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Which relationship or statement best describes delta s for the following reaction:
zalisa [80]

Answer:

b) Delta S < 0

Explanation:

The change in the entropy (ΔS) is related to the change in the number of gaseous moles of the reaction: Δn(g) = n(g, products) - n(g, reactants).

  • If Δn(g) > 0, the entropy increases (ΔS > 0).
  • If Δn(g) < 0, the entropy decreases (ΔS < 0).
  • If Δn(g) = 0, there is little or no change in the entropy

Let's consider the following equation.

2 H₂S(g) + 3 O₂(g) → 2 H₂O(g)

Δn(g) = 2 - 5 = - 3. Since Δn(g) < 0, the entropy decreases and ΔS < 0.

4 0
3 years ago
HELP PLZ ASAP<br> will give brainliest
horrorfan [7]

Answer:

I believe that it would be the third option down.

Explanation:

The thermal energy is in constant motion in the COOLER room, and when the desired temperature in the room is reached, it stops.

8 0
3 years ago
How can you make an item that is made of magnetic material become a permanent magnet instead of a temporary magnet? *
zepelin [54]

You can put it in a very strong magnetic field.

8 0
3 years ago
How do I answer question 4
lidiya [134]

One box is 120g.

mass of 126 boxes = 126*120 = 15120 g

(note: used an additional significant figure when first digit is a 1, so four significant figures)

Using the conversion 1 lb. = 453.6 g/lb

15120g = 15120 g / (453.6 g/lb) = 15120 g * (1/453.6) lb/g = 33.3 lbs. (3 significant figures)

3 0
3 years ago
Please help me ..If you don't have a question or something to say just comment don't steal my points . It's not fair. Here are t
astra-53 [7]

1.

1.20 \: mol \times  \frac{6.02 \times  {10}^{23} }{1 \: mol}  = 7.224 \times  {10}^{23} atoms

2.

9.25 \times  {10}^{25 \:} molecules \times  \frac{1 \: mol}{6.02 \times  {10}^{23} }

= 153.654485 \: moles

3.

molar mass = 3(24.31) + 127.60 + 5(32.07)

molar mass = 360.88 g

4.

molar mass = 3(58.93) + 2(30.97) + 8(16.00)

molar mass = 366.73 g

5.

molar mass = 98.09

125 \: g \times  \frac{1 \: mol}{98.09 \: g}  = 1.274339892 \: moles

//

I'm too lazy to do the rest but you should get a general idea of how to do it.

Also, round as you wish!

3 0
3 years ago
Read 2 more answers
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