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Tresset [83]
3 years ago
9

Please Help Me!!!!

Mathematics
1 answer:
ra1l [238]3 years ago
5 0
2. WXZ=YXZ
3.  Reflexive property of equality
(if they are angles)-
4. WXZ=YXZ ~~Reason- Congruent angles have equal number of degrees
(if they are triangles-more likely judging by the problem)-
4. Triangle WXZ=YXZ ~ Reason- SAS Congruence Postulate
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Which numbers are a distance of 3 units from 12 on the a number line?
Mamont248 [21]
It would be B, hope i could help out.
3 0
3 years ago
Read 2 more answers
Verify the identity. <br><br>cot. (x - (pi/2)) = -tan x<br><br>Please, help me!!!
Leya [2.2K]

Answer:

cot . (x- π/2)= - tanx

Step-by-step explanation:

cot . (x- π/2)= - tanx

cot .x - cot π/2= - tanx

cot π/2= 1/tanπ/2

But tan π/2= ∞

cot π/2 = 1/∞= 0

cotx - 0= - tanx

cot x = - tanx

cosx/sinx= - sinx/cosx             Putting values of cot and tan

cosx/ sinx ( sinx/cos x) = -sinx/cos x  (sinx/cos x )  

Multiplying both sides with  sinx/cos x    

1= - sin²x/cos²x

cos²x= - sin²x                 as cosx = -sinx

5 0
3 years ago
The tyre of a car wheel has an outer diameter of 30 cm . How many times will the wheel rotate on a journey of 5 km
faltersainse [42]

Answer:

5305.1647 times

Step-by-step explanation:

The Circumference of a circle : πd

d = diameter of circle = 30 cm

Circumference of wheel = π * 30cm = 94.247779 cm

1km to cm

1km = 100000cm

5 km = 500000 cm

Hence, number of times wheel rotate on a 5km journey :

500000 cm / 94.247779 cm

= 5305.1647 times

3 0
3 years ago
4. Using the geometric sum formulas, evaluate each of the following sums and express your answer in Cartesian form.
nikitadnepr [17]

Answer:

\sum_{n=0}^9cos(\frac{\pi n}{2})=1

\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=0

\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})=\frac{1}{2}

Step-by-step explanation:

\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))

=\frac{1}{2}(\frac{1-e^{\frac{10i\pi}{2}}}{1-e^{\frac{i\pi}{2}}}+\frac{1-e^{-\frac{10i\pi}{2}}}{1-e^{-\frac{i\pi}{2}}})

=\frac{1}{2}(\frac{1+1}{1-i}+\frac{1+1}{1+i})=1

2nd

\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}

=\frac{1-1}{1-e^{\frac{i2\pi}{N}}}=0

3th

\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))

=\frac{1}{2}(\frac{1-0}{1-i}+\frac{1-0}{1+i})=\frac{1}{2}

What we use?

We use that

e^{i\pi n}=cos(\pi n)+i sin(\pi n)

and

\sum_{n=0}^k r^k=\frac{1-r^{k+1}}{1-r}

6 0
4 years ago
The formula for the volume of a rectangular prism is V = lwh. Which is the equivalent equation solved for h?​
wel

Answer:

V /(lw) = h

Step-by-step explanation:

V = lwh

Divide each side by lw

V/ ( lw) = lwh/(lw)

V /(lw) = h

4 0
3 years ago
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