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nydimaria [60]
3 years ago
14

What is the area of one side is 5 m and the other side is 50 cm

Mathematics
1 answer:
raketka [301]3 years ago
7 0

Step-by-step explanation:

5m=500cm

Area=length x length

500m x 50cm=25000cm^2

OR

250m^2

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How any is?<br> 8m + 27 = 2m - 3 <br> with procedure and testing
givi [52]
8m+27= 2m-3
take 2m and subtract it from 8m, this gives you 6m. now your equation is 6m+27=-3.
subtract 27 from -3, this will make it 6m=-30.
divide 30 by 6. this gives you your answer. m=-5, because -30 divided by 6 equals -5.
now to test it you can plug -5 into the equation in place of M. 8 times -5 equals -40, plus 27 equals -13. 2 times -5 equals -10 plus -3 equals -13.
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You will now because the sides are equal. All sides must be equal to be congruent.

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2 years ago
The open tray shown in the illustration is to be manufactured from a 18-by-19-inch rectangular sheet of metal by cutting squares
defon
Answer: You should cut out squares that are 4 inches by 4 inches.

One of the ways to do this problem is write and graph an equation. We can write an equation for the volume of this shape and then use a graphing calculator to graph it. If we look where the graph crosses 440, we will have our solution.

The volume needs to be 440. If we let x equal the side of the square that is cut out, we have the following dimensions.

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How do you solve 3 times 2/4
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There were 6 purple socks and 4 oraange socks without looking and then another without looking (or replacing the first). What is
shusha [124]

Answer:

The probability that he picked 2 purpled socks is <u>0.33</u>.

Step-by-step explanation:

Given:

Number of purple socks, n(P) = 6

Number of orange socks, n(O) = 4

Two socks are picked without replacement.

Now, total number of socks, n(T)=N(P)+n(O)=6+4=10

Probability of picking the first cap as purple cap is given as:

P(P1)=\frac{n(P)}{n(T)}\\\\P(P1)=\frac{6}{10}=\frac{3}{5}

Since there is no replacement, the number of socks decreases by 1. Also, if the first sock picked is purple, then number of purple socks is also decreased by 1.

Therefore, probability of picking the second cap as purple cap is given as:

P(P2)=\frac{n(P)-1}{n(T)-1}\\\\P(P2)=\frac{5}{9}

Now, probability that both the picked caps are purple is given by their probability product. This gives,

P(P1\ and\ P2)=P(P1)\times P(P2)\\\\P(P1\ and\ P2)=\frac{3}{5}\times\frac{5}{9}\\\\P(P1\ and\ P2)=\frac{3}{9}=\frac{1}{3}=0.33

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