C I guess
I don’t understand
a. Let 
be a random variable representing the weight of a ball bearing selected at random. We're told that 
, so
where 
. This probability is approximately
b. Let 
be a random variable representing the weight of the 
-th ball that is selected, and let 
be the mean of these 4 weights,
The sum of normally distributed random variables is a random variable that also follows a normal distribution,
so that
Then
c. Same as (b).
Answer:
Step-by-step explanation:
StartFraction 2 Over 5 EndFraction plus p equals StartFraction 4 Over 5 EndFraction plus StartFraction 3 Over 5 EndFraction
- 2/5 + p= 4/5 + 3/5p
- p - 3/5p = 4/5 - 2/5
- 2/5p = 2/5
- 2p = 2
- p = 1
Answer is 1
Answer:
18 month loan with a 13% annual simple interest rate
Step-by-step explanation:
Answer:
100
Step-by-step explanation:
if SP>CP,
It is profit [SP - CP = Profit]
if CP>SP,
It is loss [CP - SP = Loss]
Here in the question CP>SP so,
loss = CP - SP
=200 - 100
= 100
