The answer to you question in true.
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Explanation:
1)The cell membrane functions as a semi-permeable barrier, allowing a very few molecules across it while fencing the majority of organically produced chemicals inside the cell. Electron microscopic examinations of cell membranes have led to the development of the lipid bilayer model (also referred to as the fluid-mosaic model). The most common molecule in the model is the phospholipid, which has a polar (hydrophilic) head and two nonpolar (hydrophobic) tails.
2) simple diffusion across the cell plasma membrane. The structure of the lipid bilayer allows small, uncharged substances such as oxygen and carbon dioxide, and hydrophobic molecules such as lipids, to pass through the cell membrane, down the concentration gradient is , by simple diffusion.
3) some molecules, such as carbon dioxide and oxygen, can diffuse across the plasma membrane directly, but others need help to cross its hydrophobic or however, because they are charged the polar, they can't cross the phospholipid part of the membrane without help .
4) during fission a copy of the DNA is made and attached to the cell membrane as well. As this cell elongate in preparation for fission, the two DNA copies are pulled apart two opposite ends of the cell. New membrane material is deposited between the two ends of the cell, and a new wall grows between them .
5) UMASS STEM-ED From Bubbles to Cell Membranes Workshop. Bubble ... dynamic nature which can't be properly appreciated in a static textbook. ... the small thread through one of the straws.
6) example of passive transport and active transport across a cell membrane so, cell membranes are semipermeable meaning they have control over what molecules can or cannot pass through. Some molecules can just drift Inn.
Answer and Explanation:
the total length of the gene is 6,000 base pairs (or) 6.0 kb and it has five exons, four introns and a 1,000 base pair length flanking region for the transcribed region.
Hence, each exon has (1500/5) = 300 by
each intron has (3500/4) = 875 by and
flanking segment (5' and 3') length for the transcribed region would be (1000/2) = 500 bp.
The gene segment is as shown in the <em>1st diagram attached below </em>
In eukaryotes, transcription takes place in the nucleus which results in the synthesis of hnRNA (heteronuclear ribonucleic acid). This hnRNA (pre-RNA) has both introns and exons, however when it is synthesized or while it is being synthesized the Spliceosomal complex removes introns from hnRNA and becomes converted into mRNA (messenger RNA) in the nucleus itself.
(<em>second diagram explains further)</em>
Now the synthesized mRNA reaches the cytoplasm. So, if mRNA collected from the nucleus and cytoplasm will have the same length of about 2,500 base pairs only. Therefore, after the commencement of northern blot analysis both mRNA will yield the same kind of result and have unique length.
Three main conditions - when the colony wants to swarm, when the colony wants to supersede its queen, and when its queen has died.
The cell uses information from a gene on chromosome to produce a specific protein.
