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Svetach [21]
3 years ago
15

3(x + 5) = 7x - 13

Mathematics
1 answer:
attashe74 [19]3 years ago
6 0

Answer:

Distributive

Step-by-step explanation:

3(x + 5) = 7x - 13   given

3x + 15 = 7x - 13   distribute

- 3x -3x   Subtraction property of equality

15= 7x - 13

+13 +13    Addition property of equality

28 = 7x  

7 7   division property of equality

4=x   simplify

x=4

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B

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Serggg [28]

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A is false

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What is 16 1/10 - 10 7/10
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3 years ago
Read 2 more answers
The recommended dosage for ceclor (cefaclor) is 30mg/kg to be given P.O. for a child weighing 32 lbs. Available: 125mg/5ml. How
andreyandreev [35.5K]

The child's weight in kilogram (kg) is equal to 14.5 kilogram. 2. The safe 24-hour dosage range for this child is 290 mg to 580 mg.

Given that the recommended dosage for ceclor is 30mg/kg to be given P.O. for a child weighing 32 lbs.

In order to determine the weight of the child, we would convert the value of the child's weight in pounds (lbs) to kilogram (kg) as follows:

1 pound = 0.4536 kilogram

32 pound = x kilogram

Cross-multiplying, we have: X = 32 × 0.4536 Child's weight, x = 14.5 kilogram.

Minimum range = 30 × 14.5 = 290 mg to 580 mg

Maximum range = 125 × 14.5 = 580 mg

Therefore, the safe 24-hour dosage range for this child is 290 mg to 580 mg.

Hence based on the calculations, we can infer and logically deduce that yes the dosage ordered safe because the safe single dose range is from 97 mg to 193 mg.

learn more about safe dosage at brainly.com/question/13186642

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Complete Question:

Ceclor (cefaclor) 100 mg p.oh is ordered for a child weighing 32 lbs.

1. What is the child's weight in kilograms (round to tenths)

2. What is safe 24-hour dosage range for this child?

3. Is the dosage ordered safe?

A. Yes

B. No, below the recommended dosage

C. No, it is for above the recommended dosage

D. More information is needed

4 0
1 year ago
If ax2 + bx + c = 0 then
Alexeev081 [22]
3x² + 10x + 6 = 0
x = -(10) ± √((10)² - 4(3)(6))
                       2(3)
x = -10 ± √(100 - 72)
                   6
x = -10 ± √(28)
              6
x = -10 ± 2√(7)
              6
x = -5 ± √(7)
           3
x = -1²/₃ ± ¹/₃√(7)






5x² - 6x + 1 = 0
x = -(-6) ± √((-6)² - 4(5)(1))
                     2(5)
x = 6 ± √(36 - 20)
               10
x = 6 ± √(16)
          10
x = 6 ± 4
        10
x = 3 ± 2
         5
x = 3 + 2    or    x = 3 - 2
         5                       5
x = 5    or    x = -1
      5                  5
x = 1    or    x = -0.2






2x² - 7x - 15 = 0
x = -(-7) ± √((-7)² - 4(2)(-15))
                       2(2)
x = 7 ± √(49 + 120)
                 4
x = 7 ± √(169)
             4
x = 7 ± 13
          4
x = 7 + 13    or    x = 7 - 13
          4                         4
x = 20    or    x = 6
       4                  4
x = 5    or    x = 1.5






x² + 4x + 1 = 0
x = -(4) ± √((4)² - 4(1)(1))
                   2(1)
x = -4 ± √(16 - 4)
                2
x = -4 ± √(12)
             2
x = -4 ± 2√(3)
             2
x = -2 ± √(3)
           2
x = -1 ± ¹/₂√(3)
x = -1 + ¹/₂√(3)    or    x = -1 - ¹/₂√(3)
4 0
3 years ago
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