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Svetach [21]
2 years ago
15

3(x + 5) = 7x - 13

Mathematics
1 answer:
attashe74 [19]2 years ago
6 0

Answer:

Distributive

Step-by-step explanation:

3(x + 5) = 7x - 13   given

3x + 15 = 7x - 13   distribute

- 3x -3x   Subtraction property of equality

15= 7x - 13

+13 +13    Addition property of equality

28 = 7x  

7 7   division property of equality

4=x   simplify

x=4

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Isabelle and her parents plan to share the cost of her college education. The annual tuition cost for the college she plans to a
oksano4ka [1.4K]

Answer:

7392

Step-by-step explanation:

just divide 5544÷.75 on a calculator however you want to do it than you will get 7392

5 0
3 years ago
A batch of 40 semiconductor chips is inspected by choosing a sample of 5 chips. Assume 10 of the chips do not conform to custome
butalik [34]

Answer:

a) 658008 samples

b) 274050 samples

c) 515502 samples

Step-by-step explanation:

a) How many ways sample of 5 each can be selected from 40 is just a combination problem since the order of selection isn't important.

So, the number of samples = ⁴⁰C₅ = 658008 samples

b) How many samples of 5 contain exactly one nonconforming chip?

There are 10 nonconforming chips in the batch, and 1 nonconforming chip for the sample of 5 be picked from ten in the following number of ways

¹⁰C₁ = 10 ways

then the remaining 4 conforming chips in a sample of 5 can be picked from the remaining 30 total conforming chips in the following number of ways

³⁰C₄ = 27405 ways

So, total number of samples containing exactly 1 nonconforming chip in a sample of 5 = 10 × 27405 = 274050 samples

c) How many samples of 5 contain at least one nonconforming chip?

The number of samples of 5 that contain at least one nonconforming chip = (Total number of samples) - (Number of samples with no nonconforming chip in them)

Number of samples with no nonconforming chip in them = ³⁰C₅ = 142506 samples

Total number of samples = 658008

The number of samples of 5 that contain at least one nonconforming chip = 658008 - 142506 = 515502 samples

6 0
2 years ago
The archway of the main entrance of a university is modeled by the quadratic equation
Scilla [17]

Answer:

B. (1,5) and (5.25, 3.94)

Step-by-step explanation:

The answer is where the 2 equations intersect.

We need to solve the following system of equations:

y = -x^2 + 6x

4y = 21 - x

From the second equation:

x = 21 - 4y

Plug this into the first equation:

y = -(21 - 4y)^2 + 6(21 - 4y)

y = -(441 - 168y + 16y^2)+  126 - 24y

y = -441 + 168y - 16y^2 +  126 - 24y

16y^2 + y - 168y + 24y + 441 - 126 = 0

16y^2 - 143y + 315 = 0

y = [-(-143) +/- sqrt ((-143)^2 - 4 * 16 * 315)]/ (2*16)

y = 5, 3.938

When y = 5:

x = 21 - 4(5) = 1

When y = 3.938

x = 21 - 4(3.938) = 5.25.

3 0
2 years ago
" four multiplied by the sum of a number and three is sixteen"
tia_tia [17]
4(x+3) = 16
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x=1
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