Answer:
y = 5x + 3
Step-by-step explanation:
The answer that belongs in the ? is 5.
Answer:
x^3 -9x^2 +14x +24
Step-by-step explanation:
(x-4)(x^2 - 5x - 6)
Multiply the x by everything in the second term
x * (x^2 - 5x - 6)
x^3 -5x^2 -6x
Multiply the -4 by everything in the second term
-4 * (x^2 - 5x - 6)
-4x^2 +20x +24
Add everything together
I like to line them up vertically
x^3 -5x^2 -6x
-4x^2 +20x +24
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x^3 -9x^2 +14x +24
Answer:
A
Step-by-step explanation:
As it is 7 people that like blue
Answer:
(i) = 3
(ii) = 20
Step-by-step explanation:
x = 1
y = -2
z = -1
(i) 4x - 3y + 7z
4(1) - 3(-2) + 7(-1)
4 + 6 - 7 = 3
(ii) 2x³ - 6y²z + 3xyz²
2(1)³ - 6(-2)²(-1) + 3(1)(-2)(-1)²
2 + 24 - 6 = 20
Answer:
- r = 12.5p(32 -p)
- $16 per ticket
- $3200 maximum revenue
Step-by-step explanation:
The number of tickets sold (q) at some price p is apparently ...
q = 150 + 25(20 -p)/2 = 150 +250 -12.5p
q = 12.5(32 -p)
The revenue is the product of the price and the number of tickets sold:
r = pq
r = 12.5p(32 -p) . . . . revenue equation
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The maximum of revenue will be on the line of symmetry of this quadratic function, which is halfway between the zeros at p=0 and p=32. Revenue will be maximized when ...
p = (0 +32)/2 = 16
The theater should charge $16 per ticket.
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Maximum revenue will be found by using the above revenue function with p=16.
r = 12.5(16)(32 -16) = $3200 . . . . maximum revenue
_____
<em>Additional comment</em>
The number of tickets sold at $16 will be ...
q = 12.5(32 -16) = 200
It might also be noted that if there are variable costs involved, maximum revenue may not correspond to maximum profit.
