It's hard to type and hard to read the "inverse tangent" function, as you've seen (above).
So, use "arctan x" instead.
Then the problem becomes: "differentiate cos (arctan x)."
You must apply first the rule for differentiating the cosine function, and next apply the rule for differentiating the arctan function:
(d/dx) cos (arctan x) = - sin (arctan x) * [1/(1+x^2)]
Answer:
almost 3 per minute but not just about there yet
Step-by-step explanation:
34/12 = 2.8333333333~
Step-by-step explanation:
m-(-3)>17
m +3>17
m >17-3
m>14
Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identity
sin²x + cos²x = 1 ⇒ sin²x = 1 - cos²x
Given
sin²x + 7cosx + 17
=1 - cos²x + 7cosx + 17
= - cos²x + 7cosx + 18 ← factor out - 1 from each term
= - (cos²x - 7cosx - 18)
Consider the factors of the constant term (- 18) which sum to give the coefficient of the cosx term (- 7)
The factors are - 9 and + 2, thus
= - (cosx - 9)(cosx + 2) ← in factored form
Answer:
z ≤ 6
Explanation:
z is less than or equal to: z ≤
z is less than or equal to six: z ≤ 6
