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malfutka [58]
3 years ago
9

What is the product of 14,560 x 10? We have to explain how we decided on the number of zeros in the products.

Mathematics
2 answers:
Vinvika [58]3 years ago
7 0
If we multiply 14,560 with 10 we will get <em>145,600</em>.
We have 10 in question we will add 1 zero in the product. the number of zeros we have on multiplicating side the number of zeros we will add in the product.
Example- 14,560 * 1000 = 14,560,000.


kkurt [141]3 years ago
7 0

Answer:

14560\times 10=145600    

Step-by-step explanation:

Given : Expression 14560\times 10

To find : What is the product of the expression and explain how we decided on the number of zeros in the products ?

Solution :

Step 1 - Write the expression,

14560\times 10

Step 2 - Multiply the terms,

=145600

The number of zero is decided on the basis of zero in the terms.

As in 14560 there is one zero and 10 has one zero.

Therefore, There are two zeros in the result.

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3 years ago
I’ve been struggling on this for a while. Someone help!
liberstina [14]

Answer:

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Step-by-step explanation:

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3 years ago
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Given that the product of two positive integers is 44, and their least common multiple is 22, what is their greatest common divi
swat32

Answer:

2

Step-by-step explanation:

For any positive numbers a,b we always have the following identity:

a\cdot b=gcd(a,b)\cdot lcm(a,b)

(gcd(a,b) denotes the greatest common divisor between a and b, and lcm(a,b) denotes the least common multiple between a and b)

In our case, we are given that a\cdot b = 44 and that lcm(a,b)=22. Plugging that in into our identity, we get:

44=gcd(a,b)\cdot 22

And so solving for gcd(a,b):

gcd(a,b)=\frac{44}{22}=2

5 0
3 years ago
Omgggg help me for brainly what’s 4 x 5 divided by 2
yanalaym [24]

Answer:

10

Step-by-step explanation:

\frac{4 x 5}{2}

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3 0
2 years ago
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If a coin is tossed 5 times, and then a standard six-sided die is rolled 4 times, and finally a group of three cards are drawn f
Step2247 [10]

Answer:  5,499,187,200

<u>Step-by-step explanation:</u>

A coin is tossed 5 times.  

There are two options (heads or tails) so the possible outcomes are: 2⁵

A six-sided die is rolled 4 times.

There are six options so the possible outcomes are: 6⁴

A group of 3 cards are drawn (without replacement).

The first outcome has 52 options, the second has 51 options, and the third has 50 options: 52 x 51 x 50

Now if we want the coin AND the die AND the cards, we have to multiply all of their possible outcomes:

     2⁵ x   6⁴  x  52 x 51 x 50

=   32 x 1296 x 132,600

=  5,499,187,200

3 0
3 years ago
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