Answer:
11 Is One Of Them
Step-by-step explanation:
198 Divided By 18 Equals 11.
The coefficients are the numbers in FRONT of the variable. That being said, it looks like it’s asking which number is next to the variable with the highest exponent (the little number). So, the answer would be 3.
Slope intercept inequality is in the form mx+b m standing for slope and b standing for y intercept
m= 4/3
b= -2 line passes (0,-2)
use y2-y1/x2-x1
(3,2)(-3,-6)
-6-2/-3-3
-8/-6
4/3 = slope
Let's set it up
y_ 4/3x-2
now the shaded area is on the LEFT side so this means that THE X has to be less than
The line is dashed which means it is not equal to!!
y >4/3x-2
plug in any (x,y) from the shaded area and see if this inequality is true
(-1,1)
1 >4/3 (-1)-2
1 >-4/3-2
1 >-4/3-6/3
1 >-10/3
Answer:
1. y' = 3x² / 4y²
2. y'' = 3x/8y⁵[(4y³ – 3x³)]
Step-by-step explanation:
From the question given above, the following data were obtained:
3x³ – 4y³ = 4
y' =?
y'' =?
1. Determination of y'
To obtain y', we simply defferentiate the expression ones. This can be obtained as follow:
3x³ – 4y³ = 4
Differentiate
9x² – 12y²dy/dx = 0
Rearrange
12y²dy/dx = 9x²
Divide both side by 12y²
dy/dx = 9x² / 12y²
dy/dx = 3x² / 4y²
y' = 3x² / 4y²
2. Determination of y''
To obtain y'', we simply defferentiate above expression i.e y' = 3x² / 4y². This can be obtained as follow:
3x² / 4y²
Let:
u = 3x²
v = 4y²
Find u' and v'
u' = 6x
v' = 8ydy/dx
Applying quotient rule
y'' = [vu' – uv'] / v²
y'' = [4y²(6x) – 3x²(8ydy/dx)] / (4y²)²
y'' = [24xy² – 24x²ydy/dx] / 16y⁴
Recall:
dy/dx = 3x² / 4y²
y'' = [24xy² – 24x²y (3x² / 4y² )] / 16y⁴
y'' = [24xy² – 18x⁴/y] / 16y⁴
y'' = 1/16y⁴[24xy² – 18x⁴/y]
y'' = 1/16y⁴[(24xy³ – 18x⁴)/y]
y'' = 1/16y⁵[(24xy³ – 18x⁴)]
y'' = 6x/16y⁵[(4y³ – 3x³)]
y'' = 3x/8y⁵[(4y³ – 3x³)]
If i am correct i think it is 3× = 78 +×-2 idk but i think it that hopefully u get it right :)