Question

A garden hose with an internal diameter of 2.5 cm is connected to a (stationary) lawn sprinkler that consists merely of a container with 28 holes, each 0.20 cm in diameter. If the water in the hose has a speed of 0.85 m/s, at what speed does it leave the sprinkler holes?

Answer 1

Answer:

4.7433 m/sec

Step-by-step explanation:

Given data

the internal diameter of garden =2.5 cm =0.025 m

radius $r_1$=  0.0125 m

it contains 28 holes each of diameter 0.20 cm =0.002 m

radius $r_2$ =0.001 m

from continuity equation

$A_1V_1=nA_2V_2$

where A is area and V is velocity

0.85×$A_1$=28 ×$A_2$×$V_2$

$V_2=\frac{A_1}{28A_2}\times V_1=\frac{r_1^2}{28r_2^2}\times 0.85=4.7433 m/sec$