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2 years ago

Someone help v

Mathematics

1 answer:

Readme [11.4K]2 years ago

8 0

I think the x represent puppy and the weight is the y

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Jane needs $20 to buy her radio. She has saved $15. What percent of the cost of the radio has she saved?

aivan3 [116]

Answer: 75%

Step-by-step explanation:

15/20 = 3/4 or 75%

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3 years ago

Read 2 more answers

If x = 2 and y = -3, what is the value of 2x^2 + 3xy – 2y^2?

sammy [17]

Answer: Given as,X=2 & Y=3,

now multiplying we get,

2xxy=2×2×3=12

Ans.) 12

Step-by-step explanation:

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2 years ago

The graph of was shifted 5 units down and 4 units to the left. What is the equation of the resulting graph?

marysya [2.9K]

Answer:

5x+4

Step-by-step explanation:

use the equation mx+b I think this is right but I really dunno

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3 years ago

A man sells two mobile phones at the same price . on one he makes a profit of 10% and on the other he invited a loss of 10%. fin

Gennadij [26K]

Answer:

I had that answer but i lost my paper

Step-by-step explanation:

sorry

4 0

2 years ago

In a survey of adults who follow more than one sport, 30% listed football as their favorite sport. You survey 15 adults who foll

maxonik [38]

Answer: 0.5

Step-by-step explanation:

Binomial probability formula :-

$P(x)=^nC_x\ p^x(q)^{n-x}$ , where P(x) is the probability of getting success in x trials , n is the total trials and p is the probability of getting success in each trial.

Given : The probability that the adults follow more than one game = 0.30

Then , q= 1-p = 1-0.30=0.70

The number of adults surveyed : n= 15

Let X be represents the adults who follow more than one sport.

Then , the probability that fewer than 4 of them will say that football is their favorite sport,

$P(X\leq4)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)\\\\=^{15}C_{0}\ (0.30)^0(0.70)^{15}+^{15}C_{1}\ (0.30)^1(0.70)^{14}+^{15}C_{2}\ (0.30)^2(0.70)^{13}+^{15}C_{3}\ (0.30)^3(0.70)^{12}+^{15}C_{4}\ (0.30)^4(0.70)^{11}\\\\=(0.30)^0(0.70)^{15}+15(0.30)^1(0.70)^{14}+105(0.30)^2(0.70)^{13}+455(0.30)^3(0.70)^{12}+1365(0.30)^4(0.70)^{11}\\\\=0.515491059227\approx0.5$

Hence, the probability rounded to the nearest tenth that fewer than 4 of them will say that football is their favorite sport =0.5

4 0

3 years ago